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Sonbull [250]
2 years ago
15

7th grade math help me please :))

Mathematics
1 answer:
Sav [38]2 years ago
8 0

Answer:

no because the absolute value of -7 is 7 which is greater than the absolute value of 6 which is 6.

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What is the image of point (4, 5) after a counterclockwise rotation of 270º about the origin?
andriy [413]
A <span>counterclockwise rotation of 270º about the origin is equivalent to a </span><span>clockwise rotation of 90º about the origin.

Given a point (4, 5), the x-value, i.e. 4 and the y-value, i.e. 5 are positive, hence the point is in the 1st quadrant of the xy-plane.

A clockwise rotation of </span><span>90º about the origin of a point in the first quadrant of the xy-plane will have its image in the fourth quadrant of the xy-plane. Thus the x-value of the image remains positive but the y-value of the image changes to negative.
Also the x-value and the y-value of the original figure is interchanged.
For example, given a point (a, b) in the first quadrant of the xy-plane, </span><span>a counterclockwise rotation of 270º about the origin which is equivalent to a <span>clockwise rotation of 90º about the origin will result in an image with the coordinate of (b, -a)</span>

Therefore, a </span><span>counterclockwise rotation of 270º about the origin </span><span>of the point (4, 5) will result in an image with the coordinate of (5, -4)</span> (option C)
3 0
3 years ago
Jimmy’s dad gave him $100 on his birthday, which is January 1. Jimmy deposited the $100 in his savings account the same day. At
aliya0001 [1]
$300 every month beginning Feb 1st until the month of June = $1800
5 0
3 years ago
Square root of 6 minus square root of 7 divided by square root of 6 plus square root of 7
zheka24 [161]
\frac{ \sqrt{6}- \sqrt{7} }{ \sqrt{6}+ \sqrt{7} } \\ &#10; Multiply \ and \ divide \ by \ the \ conjugate. \\ &#10; =\frac{ \sqrt{6}- \sqrt{7} }{ \sqrt{6}+ \sqrt{7} } \times \ \frac{ \sqrt{6}- \sqrt{7} }{ \sqrt{6}- \sqrt{7} } \\ &#10;=
\frac{( \sqrt{6}- \sqrt{7})^2 }{ \sqrt{6}^2 - \sqrt{7}^2 }} \\ &#10; =\frac{( \sqrt{6}- \sqrt{7})^2 }{-1} \\ &#10; =-( \sqrt{6}- \sqrt{7})^2 \\ &#10; = -( \sqrt{6}^2-2( \sqrt{6} \sqrt{7}+ \sqrt{7}^2 \\ &#10; =-(6 -2 \sqrt{42} +7) \\ &#10; =-6+2 \sqrt{42}-7 \\ &#10; =-13+2 \sqrt{42} \\ &#10;Answer: \ -13+2 \sqrt{42}

6 0
3 years ago
What is the line parallel to 2x + 3y = 12
lesya692 [45]
I hope this is helpful

6 0
3 years ago
At a video store, you have two options for renting movies. You can pay $4 per movie, or you can pay a one-time membership fee of
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Let x stand for a movie.

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x = 4

After 4 movies, the membership will cost less.


7 0
3 years ago
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