All categories

3 years ago

Which of the following equations matches the table below?

Mathematics

1 answer:

taurus [48]3 years ago

7 0

Answer:

i cant see it

Step-by-step explanation:

You might be interested in

2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

(a) The books in any order

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

(b) The mathematics book, not together

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

(c) The novels must be together and the chemistry books, together

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

(d) The mathematics must be together and the chemistry books, not together

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

2 years ago

Start with the following statement: Vertical angles are congruent. a.State the conditional and three other forms of the statemen

WARRIOR [948]

There are three kinds of statement that we could construct base on the given where as Vertical angels are congruent. First is converse: If angle 1 is 90 degree then angle 2 is 90. Second is Inverse: If angle 2 is not 90 then angle 1 is not. Third is Contrapositive: If angle 2 is not 90 then angle 1 is not 90 also.

8 0

3 years ago

Please helpppp Extra points and brainleist

vladimir1956 [14]

Answer:

Step-by-step explanation:

x² - 4x - 7 = 0

(x - 2)² = 11

5 0

3 years ago

Drag each expression to show whether it is equivalent to −2.6−(−5.9) -2.6 x - -5.9 x , −2.6+(−5.9) -2.6 x + -5.9 x , or neither.

vredina [299]

Answer:

$-2.6x-(-5.9x)$ is equivalent to $-2.6x+5.9x$ and $5.9x+(-2.6x)$

$-2.6x+(-5.9x)$ is equivalent to $-2.6x-5.9x$ and $-5.9x+(-2.6x)$ .

The expressions which are equivalent to neither:

$-5.9x+2.6x$ and $5.9x-(-2.6x)$

Step-by-step explanation:

Given the expressions:

1) $-2.6x-(-5.9x)$

2) $-2.6x+(-5.9x)$

To find:

The expressions equivalent to the given expressions.

or the expressions which are not equivalent to any of the given expressions.

Solution:

First of all, let us solve the brackets from the given expressions.

$-2.6x-(-5.9x)$ can be written as $-2.6x+5.9x$ (because when we multiply a negative sign with negative, it becomes positive.)

Similarly $-2.6x+(-5.9x)$ can be written as $-2.6x-5.9x$ (because when we multiply a positive sign with negative, it becomes negative.)

Therefore, the answer is:

$-2.6x-(-5.9x)$ is equivalent to $-2.6x+5.9x$ and $5.9x+(-2.6x)$

$-2.6x+(-5.9x)$ is equivalent to $-2.6x-5.9x$ and $-5.9x+(-2.6x)$ .

The expressions which are equivalent to neither:

$-5.9x+2.6x$ and $5.9x-(-2.6x)$

7 0

3 years ago

Set X consists of 100 numbers. The average (arithmetic mean) of set X is 10, and the standard deviation is 4.6. Which of the fol

kompoz [17]

Answer:

E. 10 and 10

Step-by-step explanation:

Standard Deviation is the square root of sum of square of the distance of observation from the mean.

$Standard deviation(\sigma) = \sqrt{\frac{1}{n}\sum_{i=1}^{n}{(x_{i}-\bar{x})^{2}} }$

where, $\bar{x}$ is mean of the distribution.

Here, since standard deviation is the ratio of the distance from the mean and sample size. So for decreasing the standard deviation we should keep numerator constant and increasing the denominator.

This can be only possible in option (E).

Hence, only Option (E) is correct.

5 0

3 years ago