Answer:
b² = a² + c² - 2ac cos B
Step-by-step explanation:
The cosine rule can be use when you are given three sides of a triangle and ask to find any angle or when you are given two sides and a included angles(the angle between the two sides given) and ask to find the length of a side.
The equation Sophia can use to solve for the side length(b) of a triangle when given two length and the included angle can be expressed below. Sophia was given two sides and an included angle and was asked to find a side length b.
For sides a, b and c the cosine rule can be represented below
a² = b² + c² - 2bc cos A
b² = a² + c² - 2ac cos B
c² = a² + b² - 2ab cos C
The equation required base on your question is
b² = a² + c² - 2ac cos B
Ln ( a^(-4) / b^1 c^1 ) =
= ln a ^(-4) - ( ln b + ln c ) =
= - 4 ln a - ln b - ln c =
= - 4 * 2 - 3 - 5 =
= - 8 - 3 - 5 = - 16
9 and 10
11 and 12
13 and 14
15 and 16
the square root of 125 is 11.18 so therefore it falls between 11 and 12
I hope this helps, i got it from a cheat sheet online
Answer:
a). We want to know how much each point was worth.
b). 
c). Each problem worth 3 points.
Step-by-step explanation:
a). We want to know how much each problem was worth. Because we have the total points of the test, and how much was the bonus. But we still don't know the worth of each problem.
b). We know that the total points of the test were 41, and the bonus 5 points. There were 12 problems on the test and we are going to use "x" for the unknown part (how many points each problem was worth).
The equation is :

Why 12x? Because if you multiply the twelve problems of the test with the worth of each one and then add the 5 points of the bonus you will obtain the total points of the test (41).
c). Now we have to solve the equation, this means that we have to clear "x":

Subtract 5 from both sides.

Finally divide in 12 both sides of the equation:

Then each problem worth 3 points.