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Doss [256]
3 years ago
12

What is the angle of rotation for the following figure 45° 60° 90° 120°

Mathematics
1 answer:
Tju [1.3M]3 years ago
4 0
I thinks the answer is 90 because the figure has. No sides and has an even number of triangles around it
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Calculate the unit rate:<br>write your answer as a decimal <br><br>1/2 mile in ever 1/3 hour​
Alexandra [31]

Answer:

unit \: rate =  \frac{distance}{time}

unit rate is similar to speed / velocity:

unit \: rate =  \frac{ (\frac{1}{2} )}{ (\frac{1}{3})} \\  \\  =  \frac{1}{2}  \div  \frac{1}{3}  \\  \\  =  \frac{1}{2}  \times  \frac{3}{1}  \\  \\  = >  { \boxed{ \boxed{unit \: rate  =   \frac{3}{2}  \: miles \: per \: hour}}}

[<em>unit</em><em> </em><em>rate</em><em> </em><em>must</em><em> </em><em>have</em><em> </em><em>units</em><em> </em><em>including</em><em> </em><em>per</em><em> </em><em><</em><em>time</em><em>></em><em> </em>]

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2 years ago
QUESTION 2<br> 84 is 30% of what number?
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100/30=3.(3)

3.(3)*84=280

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3 years ago
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54.00 for tickets write a unit rate for the situation
schepotkina [342]
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5 0
3 years ago
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Question 1: The water level in a tank can be modeled by the function h(t)=4cos(+)+10, where t is the number of hours
Amanda [17]

Answer:

Question 1: The hours that will pass between two consecutive times, when the water is at its maximum height is π hours

Question 2: Sin of the angle is -0.8

Step-by-step explanation:

Question 1: Here we have h(t) = 4·cos(t) + 10

The maximum water level can be found by differentiating h(t) and equating the result to zero as follows;

\frac{\mathrm{d}  h(t)}{\mathrm{d} t} = \frac{\mathrm{d} \left (4cos(t) + 10  \right )}{\mathrm{d} t} = 0

\frac{\mathrm{d}  h(t)}{\mathrm{d} t} = - 4 \times sin(t) = 0

∴ sin(t) = 0

t = 0, π, 2π

Therefore, the hours that will pass between two consecutive times, when the water is at its maximum height = π hours.

Question 2:

B = (3, -4)

Equation of circle = x² + y² = 25

Here we have

Distance moved along x coordinate = 3

Distance moved along y coordinate = -4

Therefore, we have;

Tan \theta = \frac{Distance \ moved \ along \ y \ coordinate}{Distance \ moved \ along \ x \ coordinate} = \frac{-4}{3}

\therefore \theta = Tan^{-1}(\frac{-4}{3}) = -53.13^{\circ}

Sinθ = sin(-53.13) = -0.799≈ -0.8.

5 0
3 years ago
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