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Doss [256]
3 years ago
12

What is the angle of rotation for the following figure 45° 60° 90° 120°

Mathematics
1 answer:
Tju [1.3M]3 years ago
4 0
I thinks the answer is 90 because the figure has. No sides and has an even number of triangles around it
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On a test Denzel answers that 3x + 6a + 7 is equivalent to 3(x + 2a +7). Is Denzel correct, why or why not? * Yes, he is correct
emmainna [20.7K]

Answer:

No, he is not correct because the constant in his answer should have been 21 not 7.

Step-by-step explanation:

3(x+2a+7)=3x+6a+21

Therefore, the correct answer is the fourth; he should have put 21.

6 0
3 years ago
Question 1<br><br> Which choice shows a 90° clockwise rotation of the figure about the point P?
Arada [10]
The third one is correct.....so go for it without hesitation
6 0
3 years ago
3.) A box in the shape of a rectangular prism has a volume of 180 cm". The length is x cm, the
Karolina [17]

Answer:

48

Step-by-step explanation:

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4 0
3 years ago
How do i write factored form for the graphs?
xxMikexx [17]
1. Take the two x-axis intersections.

For Q 31 it is:
x = -4 and x = 0

2. Reorganise the previous equations

x +4 = 0 and x = 0

3. Put the x side in brackets

x(x+4)

4. Done

—-

Q 32

x = -1
x = 5

x + 1 = 0
x - 5 = 0

(x+1)(x-5)
5 0
3 years ago
Read 2 more answers
find the equation of the sides of an isosceles right angled triangle whose vertex is (-2,-3) and the base is on the line x=0​
Serggg [28]

Answer:

AC:y=x-1  CB:y=-x-5 AB:x=0

Step-by-step explanation:

Consider the triangle. The base AB is on the line x=0, the vertex C is (-2,-3)

The side AC is equal to BC. The angle ACB is 90 degrees. If the base is on the line x=o, it is on the axis Y.Explore the distance from the point C to the AB

c(-2,-3), the distance to the axis Y is equal to the modul of the coordinate x (-2), it is 2. The coordinates of point projected by the point C to the axis Y is N(0,-3). The modul of the height is 2, the height of the isosceles triangle to the base is the bisectrix, so the angle BCA is 90/2=45degrees, CBA is 180-90-45=45 degrees too

the heigt CN is equal to side NB, NB=2

Suppose B is (0,y) (x=0 because the base is on this line)

THe modul of the vector NB is equal to sqrt ((0-0)^2+(y+3)^2)= 2

modul (y+3)= 2

y=-1 or y=-5

(0,-1), (0,-5) - two points, one of them (suppose B) is (0,-5) when A is (0,-1) (A is remote from the point N on the same distance with B, because AB is the median too)

Find CB and AC

Use the equation for AC

(x-0)/(-2-0)= (y+1)/(-3+1)

x/-2= (y+1)/-2

x=y+1

y=x-1

For CB

(x-0)/ (-2-0)= (y+5)/ (-3-(-5))

x/-2= (y+5)/2

-x=y+5

y=-x-5

7 0
2 years ago
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