Answer: 71/30 or 2 and 11/30 yards
Work:
You need to add each fraction together in order to find the total amount of fabric. You should do this by finding common denominators (the number on the bottom of the fraction) and then combining fractions.
Since the order of adding doesn't matter, you should combine the fractions that are the easiest first. Start with adding 1/2 and 1/3. The common denominator is 6, since that is the LCM of 2 and 3. The fractions then become 3/6 and 2/6 which combine into 5/6. It is then easy to add the other 5/6 of a yard from the question to the 5/6 you have just found into 10/6.
Then come over to the 3/10 and 2/5 yard pieces which can be easily added together using 10 as the common denominator. These two fractions added together become 7/10.
The final step is to add the 7/10 plus the 10/6. The common denominator is 30, as it is the LCM of 10 and 6. The new fractions become 21/30 plus 50/30 which equals 71/30.
Answer:
Step-by-step explanation:
Find the slope of the line AB.
<u>The slope:</u>
- m = (11 - 9)/(11 - 7) = 2/4 = 1/2
Since the altitude is perpendicular to AB, it has a slope of -2.
The line with the slope of -2 and passes through point C(6, 16).
<u>Use point-slope equation to find the line:</u>
- y - 16 = -2(x - 6)
- y - 16 = -2x + 12
- y + 2x = 16 + 12
- 2x + y = 28
A = 2, B = 1, C = 28
Answer:
<h3>55 secs</h3>
Step-by-step explanation:
Given the elevation h (in feet) of the balloon modeled by the function h(x)=−6x+330, we can calculate the time it takes the balloon to reach the ground. The hot air balloon hits the ground at h(x) = 0.
Substitute h(x) = 0 into the modeled expression and find x as shown;
h(x)=−6x+330
0 = −6x+330
6x = 330
Divide both sides by 6
6x/6 = 330/6
x = 55 seconds
Hence the hot air balloon hits the ground after 55 seconds
Answer:
140°
Step-by-step explanation:
155°-15° =140°
Answer:
<em>(D). (3, 1) </em>
Step-by-step explanation:
y ≤ 3x - 4
<u><em>(A). (0, 4)</em></u>
4 ≤ 3(0) - 4
4 ≤ - 4 <u><em>(False statement)</em></u>
<u><em>(B). (-2, 0)</em></u>
0 ≤ 3(- 2) - 4
0 ≤ - 10 <u><em>(False statement) </em></u>
<u><em>(C). (0, 0)</em></u>
0 ≤ 3(0) - 4
0 ≤ - 4 <u><em>(False statement)</em></u>
<u><em>(D). (3, 1)</em></u>
1 ≤ 3(3) - 4
1 ≤ 5 <u><em>(True statement) </em></u>