9514 1404 393
Answer:
Step-by-step explanation:
The measure of an inscribed angle (QTR) is half the measure of the arc it intercepts. The measure of an arc is the same as the measure of the central angle it intercepts. So, we have ...
∠QSR = 2×∠QTR
∠QSR = 2×39°
∠QSR = 78°
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Sides SQ and SR are radii of circle S, so are the same length. That means triangle QRS is an isosceles triangle and the base angles SQR and SRQ are congruent. The sum of angles in a triangle is 180°, so we have ...
∠QSR + 2(∠SQR) = 180°
78° + 2(∠SQR) = 180° . . . . fill in the value we know
2(∠SQR) = 102° . . . . . . . . . subtract 78°
∠SQR = 51° . . . . . . . . . . . . .divide by 2
The picture is super blurry so i can’t see anything
Answer:
75
Step-by-step explanation:
did it 5 mins ago
3x=x+40
Subtract x from both sides
2x=40
Divide both sides by 2nto get x by itself
x=2
Plug 2 in for x
m∠4 = (3x)
m∠4 = 3(2)
Solve
m∠4 = 6
Focus of a parabola:

where vertex (h,k) p is the distance from vertex to focus