The Most Logical Answer is B
C 10/36
Explanation
5x2=10
12x3=36
Ten over 36
Hello there!
So, let's start off with the first one:
A) 60% of One - half x
I believe a couple of possible equations would be: 0.60*1/2x or 0.60*0.5x. 1/2 and 0.5 both equal half of a number. The 0.60 would equal 60%. I'll plug 10 into x of both equations to see what I come up with:
First Equation:
1/2 * 10/1 = 10/2 or 5.
0.60 * 5 = 3
Second Equation:
0.5 * 10 = 5
0.60 * 5 = 3
So they both come up with the same answer, so that makes them both equal, which makes them both possible equations.
B) 7 times z reduced by a third of the product
7z - 1/3 seems like a good equation. Let me plug in 5 for z to solve:
7 * 5 = 35
Convert 35/1 into 105/3 by multiplying both sides by 3
105/3 - 1/3 = 104/3 (approx. 34.7)
C) Three-fourths of V subtracted from 6 times two-ninths
A good equation for this would probably be (6*2/9)-3/4v. I'll plug 5 into v to show how we would solve the equation:
6/1 * 2/9 = 12/9 or 1 1/3.
3/4 * 5/1 = 15/4 or 3 3/4.
(Use the fractions 16/12 and 45/12 as 16/12 = 12/9 and 15/4 = 45/12)
16/12 - 45/12 = -29/12 or −<span>2 <span>5/12</span></span>
D) Sum of 2x, (2/3 + 5) and 11-x
I think the right equation for this would be 2x + (2/3 + 5) + 11-x. Plug in 3 for x to solve:
(Use 15/3 when adding 2/3 and 5 because 5 = 15/3)
2/3 + 15/3 = 17/3 or 5 2/3
2 * 3 = 6
11 - 3 = 8
(Use 18/3 and 24/3 when adding up 6 + 5 2/3 + 8 as 6 = 18/3 and 8 = 24/3
17/3 + 18/3 + 24/3 = 59/3 or 19 2/3
Sorry if this confused you xD but, basically, the possible equations are as follows:
1 = 0.60*1/2x or 0.60*0.5x
2 = 7z - 1/3
3 = <span>(6*2/9)-3/4v
</span>4 = 2x + (2/3 + 5) + 11-x
I hope this helped! If not, I'm very sorry. Algebra isn't my strong suit ^.^'
Answer:
g(-9) = 1
Step-by-step explanation:
g(-9) is the value of the function at x = -9
Go over the x = -9 and go up until you hit the blue line
Read the value of y
g(-9) = 1
Answer:
You make a factor tree for (-)40 where the factors of -40 are -8 and +5. This becomes (x+5)(x-8) which can be multiplied to get back to the starting point.
