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Setler [38]
3 years ago
12

Please show your work

Mathematics
1 answer:
bogdanovich [222]3 years ago
6 0

Answer:

B) 40

Step-by-step explanation:

Angle X and the missing angle inside the triangle are equal as the are opposite angles.

Therefore,

180 - 65 - 75 = 40

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Lauren is shopping and finds 6 bracelets, 2 pairs of earrings, and 3 necklaces that she likes. How many ways can Lauren select 4
Grace [21]
Because it does not specify that she has to choose one or two from each category all pieces of jewelry can be treated as choices in a combination set.

the formula for a combination is

C(n,r)= \frac{n!}{r!(n-r)!}

where n is a total number of choices ( 11 ) 
and r is number chosen out of those choices (4)
 so

C(11,4)= \frac{11!}{4!(11-4)!} 

She has 330 possible choices  to come home with 4 pieces of jewelry



5 0
4 years ago
Read 2 more answers
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Mariulka [41]

Answer:

-282y

Step-by-step explanation:

8 0
3 years ago
Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?
valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

X/2 > 90°

x>180°

x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0
4 years ago
Describe the possible values for x and y when ∣x − y ∣ &gt; 0. What does it mean when ∣x − y ∣ = 0? Can ∣x − y ∣ &lt; 0? Explain
Vilka [71]
The possible values for | x-y | > 0 is any number above 0. x must be greater than y. When | x-y | = 0, That means that x and y are equal to each other. | x-y | can not be less than 0, but it can equal 0.

Hope that this helped!
4 0
3 years ago
Find the greatest common factor of each set of numbers 27,36,72
7nadin3 [17]
The answer is to the question is 9
6 0
4 years ago
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