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JulsSmile [24]
3 years ago
13

what are reflex angles? I don't know what they are so just tell me in the most simple way possible of what reflex angles are so

I can understand plz. Also can you tell in the simplest way how to solve a reflex angle problem? Thank you, Have a good day :)
Mathematics
2 answers:
erma4kov [3.2K]3 years ago
8 0

the same thing as an obtuse angle!

Step-by-step explanation:

a angle that is more than 90 degrees but less than 180 degrees. not sure what a reflex problem is but if you give it to me I can try and help!

Bad White [126]3 years ago
7 0

Answer:

A reflex angle is an angle that is always bigger than 180 but smaller than 360. So for example 270 is a reflex angle.

Step-by-step explanation:

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Darina [25.2K]

Answer:

359 is your answer

Step-by-step explanation:

Have a good day ;-)

3 0
3 years ago
Read 2 more answers
Solve the equation below for x. <br> 500 = 25e ^ (2x)
Zigmanuir [339]

Answer:

x = i π n + log(20)/2 for n element Z

Step-by-step explanation:

Solve for x:

500 = 25 e^(2 x)

500 = 25 e^(2 x) is equivalent to 25 e^(2 x) = 500:

25 e^(2 x) = 500

Divide both sides by 25:

e^(2 x) = 20

Take the natural logarithm of both sides:

2 x = 2 i π n + log(20) for n element Z

Divide both sides by 2:

Answer: x = i π n + log(20)/2 for n element Z

7 0
3 years ago
X÷-1.2= -0.3 i need help with this asap pls and thank you ​
Aleks [24]

0.3×1.2

=0.36

−0.3,1.2→Negative

−0.36

3 0
2 years ago
50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle
aalyn [17]

Answer:

EF=4\sqrt{3}

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

A_{\text{rect}}=8(6)=48\text{ cm}^2

The area of the triangle is 1/4 of this. Therefore:

\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

\displaystyle 12=\frac{1}{2}(DE)(DF)

Since DE = DF:

24=DF^2

Thus:

DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

(DE)^2+(DF)^2=(EF)^2

Therefore:

(2\sqrt6)^2+(2\sqrt6)^2=EF^2

Square:

24+24=EF^2

Add:

EF^2=48

And finally, we can take the square root of both sides:

EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}

6 0
3 years ago
Read 2 more answers
|8m| = 104 absolute value
DENIUS [597]

Answer:

m=13

Step-by-step explanation:

Ok

l8ml=104

8m=104

⁻⁻⁻  ⁻⁻⁻

8        8

m=13

6 0
3 years ago
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