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3 years ago

What is 3 over 7 divided by 4 over 5? PLEASEEE HELP MEEEE!!

Mathematics

2 answers:

Setler79 [48]3 years ago

8 0

Answer: As a decimal 0.53 and a fraction 15/28

Talja [164]3 years ago

7 0

The answer should be 15/28

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Simplify <img src="https://tex.z-dn.net/?f=%28r%5Cfrac%7B1%7D%7B2%7D4" id="TexFormula1" title="(r\frac{1}{2}4" alt="(r\frac{1}{2

Katena32 [7]

Hello!!

════ ⋆★⋆ ════

$\mathbb{A~N~S~W~E~R~:}$

$= r$ · $2$

➡ $\Huge \sf \mathbb \color{}\underline{\colorbox{ANSWER~WITH~EXPLANATION ~!}{}}$

$\mathfrak{apply~the~fraction~rule: }$ $a$ $\frac{b}{c} =\frac{a~. ~b }{c}$

$\mathfrak{apply~rule: }$ $a$ · $1 = a$

$r$ · $1$ · $4 = r$ · $4$

$=\frac{r~.~4}{2}$

$\mathfrak{divide~the~numbers~: }$ $\frac{4}{2} = 2$

$= r$ · $2$

So, your answer will be is :

$= r$ · $2$

$\color{}{Hope\:it\:helps. ..}$

#LearnWithBrainly

$\mathbb{A~N~S~W~E~R~:}$

$\mathfrak{Jace}$

4 0

3 years ago

Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.

alina1380 [7]

Answer:

The answer is $x=a^{-1}cb^{-1}$ .

Step-by-step explanation:

First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element $g\in G$ there exist another element, denoted by $g^{-1}$ such that $gg^{-1}=e$ , where $e$ stands for the identity element of G.

So, given the equality $axb=c$ we make a left multiplication by $a^{-1}$ and we obtain:

$a^{-1}axb =a^{-1}c.$

But, $a^{-1}axb = exb = xb$ . Hence, $xb = a^{-1}c$ .

Now, in the equality $xb = a^{-1}c$ we make a right multiplication by $b^{-1}$ , and we obtain

$xbb^{-1} = a^{-1}cb^{-1}$ .

Recall that $bb^{-1}=e$ and $xe=x$ . Therefore,

$x=a^{-1}cb^{-1}$ .

6 0

3 years ago

Which function has a range of {yly < 5}?

Alexeev081 [22]

Answer:

f(x) = -(x-4)^2 + 5

Step-by-step explanation:

The function $f(x) = -(x-4)^2 + 5$ is a quadratic function. Its graph looks like a parabola. The graph has a vertex of (4,5) and opens up downward.

Proving that $f(x) = -(x-4)^2 + 5 \le 5$ for all x:

$x^2 \ge 0 \Rightarrow (x-4)^2 \ge 0 \Rightarrow -(x-4)^2 \le 0 \Rightarrow -(x-4)^2 + 5 \le 5.$

8 0

3 years ago

What is the answer for Ab•2b

7nadin3 [17]

Answer:

2Ab^2

Step-by-step explanation:

I think its right

4 0

3 years ago

Jill estimated she would spend $50.00 a month on clothing. However, at the end of the year she discovered she actually spent $71

RideAnS [48]

50$ per month for 12 years would mean she spent only (50 x 12) 600$ per year.

She actually spent $711, her forecast was off target by (600-7111) $111.

She exceeded her budget by $111

5 0

3 years ago