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viktelen [127]
3 years ago
12

X + 3 < 15 what is 4

Mathematics
1 answer:
professor190 [17]3 years ago
6 0

Answer:

X = > 12 because 15 - 3 = 12 and if X was more than 12 it would be wrong.

Step-by-step explanation:

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Solve the equation.
mylen [45]

-9/15y+3/21=5/15y-14/21

Move 5/15y to the other side. Sign changes from +5/15y to -5/15y

-9/15y-5/15y+3/21=5/15y-5/15y-14/21

-14/15y+3/21=-14/21

Move 3/21 to the other side. Sign changes from +3/21 to -3/21.

-14/15y+3/21-3/21=-14/21-3/21

-14/15y=-14/21-3/21

-14/21-3/21=-17/21

-14/15y=-17/21

Multiply both sides by -15/14

-14/15y(-15/14)

Cross out 15 and 15, divide by 15 then becomes 1

Cross out 14 and 14, divide by 14 then becomes 1

1*1*y=y

-17/21*-15/14

Cross out 15 and 21 , divide by 3. 15/3=2, 21/3=7

17/7*5/14=85/98

Answer: c. y=85/98

7 0
3 years ago
Help pls I no it’s simple but I don’t understand pls look at the pictures or image pls pls number 1 pls
NeTakaya

Answer: The answer would be No, Yes, No.

Step-by-step explanation:

Look at the grid, you can see that it has 100 units in all.

0.42 equals 21/50, so they are both wrong. The denominator would have to be 100. The only logical one would be the second one.

4 0
3 years ago
The diagram shows a triangle.<br><br> What is the value of z?
Damm [24]

Answer:

z=31°

Step-by-step explanation:

32°+117°+z=180°{ sum of angle of triangle}

z=180-149

z=31°

<h2>stay safe healthy and happy.</h2>
6 0
3 years ago
Read 2 more answers
Tyler is offered to choose between three boxes that look identical. The first box contains 1 red pills and 19 blue pills, the se
Dafna1 [17]

Answer:

A) 0.15

B) 0.36

Step-by-step explanation:

First Box consist 1 red pills and 19 blue pills

second box consist 6 red pills and 14 blue pills

Third box consist 2 red pills and 18 blue pills

a) Prob ( randomly chosen pill is red) = \frac{1}{3} \times \frac{1}{20} + \frac{1}{3} \times \frac{6}{20} + \frac{1}{3} \times \frac{2}{20}

\frac{1}{60} (1+6+2) = 0.15

b)Prob ( 1 reds and 10 blue pilss) =\frac{1}{3} \frac{^1C_1\times ^{19}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^6C_1\times ^{14}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^2C_1\times ^{18}C_{10}}{^{20}C_{11}}

= \frac{1}{3} 1.106 = 0.368

7 0
3 years ago
Please help, I’m new to this app so O
umka2103 [35]

Answer:

x=10 5x=50 2x=20

Step-by-step explanation:

5x+2x+110=180

180-110=70

7x=70

x=10

5*10=50

2*10=20

5 0
3 years ago
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