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3 years ago

Earl runs 30 meters in 20 seconds. How many meters does Earl run per second?

2 answers:

4 0

You would divide 30 meters by 20 seconds. If you want to know how many meters he can run per second, you divide the amount ran (30 meters) by the amount of seconds (20 seconds). This would tell you the amount per second.

The answer would be 1.5 meters/second.

Kipish [7]3 years ago

3 0

- - He runs 1.5 meters each second.

- Solve:
Divide 30/20
=1.5
To answer this we will divide the amount of meters by the amount of seconds. Then your answer will be the amount of meters Earl runs per second. Then we will check our work. Lets do it:-

30 ÷ 20 = 1.5
1.5 meter per second.

CHECK OUR WOK:-

1.5 × 20 = 30
We were RIGHT!!

So, 1.5 meters per sec.

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In testing the hypothesis H 0 colon mu subscript D less or equal than 5 space v s. space H 1 colon mu subscript D greater than 5

malfutka [58]

Answer:

The null hypothesis failed to be rejected (P-value=0.014).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The null and alternative hypothesis are:

$H_0: \mu=5\\\\H_a:\mu> 5$

The significance level is α=0.01.

The sample has a size n=20.

The sample mean is M=9.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=7.5.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{7.5}{\sqrt{20}}=1.677$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{9-5}{1.677}=\dfrac{4}{1.677}=2.385$

The degrees of freedom for this sample size are:

$df=n-1=20-1=19$

This test is a right-tailed test, with 19 degrees of freedom and t=2.385, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.385)=0.014$

As the P-value (0.014) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

3 0

3 years ago

Omg please help me im literally dying

Karolina [17]

Answer:

(-2,3)

Step-by-step explanation:

Multiply -3x+4y=18 with 2:

-6x+8y=36

Add -6x+8x=36 and 6x+2y=-6

10y=30

y=3

So y=3 we can replace y with 3 on any of these two equations:

6x+6=-6

Move the 6 to the other side:

6x=-12

x=-2

So the solution is

(-2,3)

Hope this helps

6 0

3 years ago

Please help with this Circle Geometry question??

user100 [1]

(i) XYZ = 180 - 64
= 116 degrees
Opposite angles in a cyclic quadrilateral add up to 180 degrees

(ii) YXZ = 23 degrees
Alternate angles in a segment are the same

(iii) OXZ = 26
XOZ = 64 x 2
= 128 degrees
The the angle at the centre is double the angle at the circumference.
180 - 128 = 52
OXZ = 52/2
= 26
Triangle OZX is an isosceles triangle

(Don't forget to include the reasons above full marks)

3 0

3 years ago

HELP PLEASEEEEEEEE!!!!!!!

Andrew [12]

Answer:

Step-by-step explanation:

$We\ know\ that\\ Mean=\frac{Total\ Sum\ of\ observations}{Total\ number\ of\ observations} \\Here,\\Total\ Sum\ of\ the\ given\ observations\ are :\\9+9+2+8+9+8+7+8+3\\=63\\Total\ number\ of\ the\ given\ observations\ are :\\=9$

$Hence,\\Mean=\frac{63}{9}\\=7$

7 0

3 years ago

Read 2 more answers

Please solve the whole page please please

Leya [2.2K]

1d) ↑ (Do the same but turned if that's easier)

1a) 199

1b) 193

1c) 217

1e) Based on the box plot, we can for example, find the lowest and greatest values, the range (largest - smallest), the mean (all values / # values), and the median middle value or q2 given by the second line in the box.

2b) 7

2c) 9.5

2d) ↑

2e) because the data is not ordered, it is difficult to determine the quartile data. Once it is ordered like 6, 7, 7, 7, 8, 8, 9, 10, 10. The data can be visualized alot easier. With the box plot we can determine q3 of the data by looking at the 3rd line, using the whiskers of the box to find the minimum and maximum values.

You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.

In this case the ordered data would be: 4,6,8,8,9,11,12,14,14,16.

[4, 6, 8, 8, 9] [] [11, 12, 14, 14, 16]

4 is the minimum, 16 is the maximum, q1 is 8, q3 is 14, and median is 10.

4) ↑

You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.

In this case the ordered data would be:

45, 45, 50, 55, 60, 70, 70, 75, 80, 85

[45, 45, 50, 55, 60] [] [70, 70, 75, 80, 85]

45 is the minimum, 85 is the maximum, q1 is 50, q3 is 75, and median is 65.

6) ↑

4 0

2 years ago