Look at it this way:
When you flip a coin, the probability of it landing with EITHER side showing
is 100%.
This leads us to the rule ...
The sum of the probabilities of
all possible outcomes is 100%.
For a coin: (probability of heads) plus (probability of tails) = 100%.
That just says: We're 100% sure that the coin will land with either
heads or tails up.
An "honest" coin gets heads 50% of the time and tails the other 50%.
But if the coin is all bent and squashed and has a feather stuck to
one side and a wad of gum on the other side so that it comes up
heads 70% of the time, then the coin isn't 'honest'. But it still has to
land EITHER heads OR tails, so the sum of the probabilities is still 100%.
So the probability of heads is 30%.
I don’t know what the question is, your just saying that
Hey there!
We can solve this problem by doing PEMDAS, which lists:
We have in this equation
Let's sp;ve this equation now!
Parentheses ↓
Exponents ↓
Division ↓
Okay now , I show you the steps so it can be easier to solve!
Good luck on your assignment and enjoy your day!
~
To start off devide both sides by M i.e
K/M=LMN/M
-> K/M=LN
Then devide by K to remove it on the left , this will end you up with M=LN/K
So the answer is (c).
Hope this helps :).
