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3 years ago

Anyone knows about this ?.

Mathematics

1 answer:

solniwko [45]3 years ago

4 0

Answer: nope

Step-by-step explanation:

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Any number is divisible by 2 is also divisible by 6 find a counter example to show that conjecture is false

likoan [24]

Answer:

Step-by-step explanation:

To be divisible by 6, an even number must also be divisible by 3. Two of every three even numbers are <em>not</em> divisible by 3, so are not divisible by 6.

5 0

3 years ago

1,3,5,7,9 what is the next term

Law Incorporation [45]

Answer:

11. This is counting only odd numbers, or counting by two starting with one.

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4 years ago

Read 2 more answers

The Class Earned $3 A Day For One Week For Their School Trip. How Much Money Did They Have By The End Of The Week?

zzz [600]

$21 because 3$x$7(numbers of days in a week)is $21. I hope this helps :)

6 0

3 years ago

The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt

Marizza181 [45]

Answer:

Exact dimensions:

$width=-1+\sqrt{7}$

$length=-1+\sqrt{7}+2$

$length=1+\sqrt{7}$

Approximate dimensions:

$width=1.64575ft$

$length=1.64575+2$

$length=3.64575ft$

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

$L=w+2$

now, we can find area

$A=L\times W$

now, we can plug it

$A=(w+2)\times w$

$A=w^2+2w$

we are given area =6

so, we can set it equal

and then we can solve for w

$w^2+2w=6$

$w^2+2w-6=0$

we can use quadratic formula

$ax^2+bx+c=0$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

$w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}$

$w=-1+\sqrt{7},\:w=-1-\sqrt{7}$

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

$width=-1+\sqrt{7}$

$length=-1+\sqrt{7}+2$

$length=1+\sqrt{7}$

Approximate dimensions:

$width=1.64575ft$

$length=1.64575+2$

$length=3.64575ft$

7 0

3 years ago

Determine a and k so the given points are on the graph of the function.

pshichka [43]

Step-by-step explanation:

Explanation:

Because

(2,6) is in the function, we can plug

6 as y

and

2 as x.

From that we get

6=a(2−1)2+k

6=a+k

Same for the next point:

12=a(3−1)2+k

12=22a+k

12=4a+k

Now we have this system of equations to solve:

a+k=6

4a+k=12

Solving it leads to the conclusion that

a=2,k=4 .

3 0

3 years ago