Answer:
The distance from the base of the statue to the ship is 771.60 ft
Step-by-step explanation:
Refer the attached figure
Height of statue AB= 250 feet
The tourist sees a ship coming into the harbor and measures the angle of depression as 18°.
So, ∠ACB = 18°
We are supposed to find the distance from the base of the statue to the ship i.e. BC
In ΔABC





BC=771.60 ft
Hence the distance from the base of the statue to the ship is 771.60 ft
The slope is (8-2)/(0-2)=-3
the y intercept is 8
the equation is y=-3x+8
the area to the left is shaded, and the line is solid, so y

-3x+8
Answer:
LN and RQ
Step-by-step explanation:
PQR is just an enlargened version of MLN
RQ is just LN but longer
x = 3
-2 | 2.2(3) -3.3 | = -6.6
-2 | 6.6 - 3.3 | = -6.6
-2 | 3.3 | = -6.6
-2 * 3.3 = -6.6
-6.6 = -6.6
7x - 8(-2 + 9) = 112
7x - 8(7) = 112
7x - 56 = 112
7x = 112 + 56
7x = 168
x 168/7
x = 24 <==