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3 years ago

What's the answer Gggggvgvvcdgjhggghhgggggggvhggggggg

Mathematics

1 answer:

docker41 [41]3 years ago

3 0

When answering things like this do the brackets first, is there are parenthesis in the brackets do those but keep it in the brackets and work regularly after

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Find the value of tan theta if sin theta = 12/13 and theta is in quadrant 2

8090 [49]

Answer:

tanΘ = - $\frac{12}{5}$

Step-by-step explanation:

Using the trigonometric identities

• sin²x + cos²x = 1, hence

cosx = ± √(1 - sin²x )

• tanx = $\frac{sinx}{cosx}$

given sinΘ = $\frac{12}{13}$ , then

cosΘ = ± $\sqrt{1-(12/13)^2}$

Since Θ is in the second quadrant where cosΘ < 0, then

cosΘ = - $\sqrt{1-\frac{144}{169} }$

= - $\sqrt{\frac{25}{169} }$ = - $\frac{5}{13}$

tanΘ = $\frac{\frac{12}{13} }{\frac{-5}{13} }$

= $\frac{12}{13}$ × - $\frac{13}{5}$ = - $\frac{12}{5}$

5 0

3 years ago

Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are

Kruka [31]

Answer:

Step-by-step explanation:

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean of type A paint

x2 = sample mean of type B paint

s1 = sample standard deviation type A paint

s2 = sample standard for type B paint

n1 = number of samples of type A paint

n2 = number of samples of type B paint

From the information given,

x1 = 75.7

s1 = 4.5

n1 = 11

x2 = 64.3

s2 = 5.1

n2 = 9

x1 - x2 = 75.7 - 64.3 = 11.4

√(s1²/n1 + s2²/n2) = √(4.5²/11 + 5.1²/9) = √4.709

Degree of freedom = (n1 - 1) + (n2 - 1)

df = (11 - 1) + (9 - 1) = 18

For the 98% confidence interval, the z score from the t distribution table is 2.552

Margin of error = 2.552√4.709 = 5.55

The upper boundary for the confidence interval is

11.4 + 5.55 = 16.95 hours

The lower boundary for the confidence interval is

11.4 - 5.55 = 5.85 hours

The correct option is

B. 5.85 hrs < μ1 - μ2 < 16.95 hrs

4 0

3 years ago

Find the optimal solution for the following problem. (Round your answers to 3 decimal places.)

Sphinxa [80]

Answer:

x=2.125

y=0

C=19.125

Step-by-step explanation:

To solve this problem we can use a graphical method, we start first noticing the restrictions $x\geq 0$ and $y\geq 0$ , which restricts the solution to be in the positive quadrant. Then we plot the first restriction $8x+10y\leq 17$ shown in purple, then we can plot the second one $11x+12y\leq 25$ shown in the second plot in green.

The intersection of all three restrictions is plotted in white on the third plot. The intersection points are also marked.

So restrictions intersect on (0,0), (0,1.7) and (2.215,0). Replacing these coordinates on the objective function we get C=0, C=11.9, and C=19.125 respectively. So The function is maximized at (2.215,0) with C=19.125.

3 0

3 years ago

What is the value of q?

hram777 [196]

Answer:

$2 \sqrt{14}$

5 0

2 years ago

Pls help me with this question

Andrei [34K]

Answer:

Step-by-step explanation:

(sin(2n) − 1) / (sin n − cos n)

-(1 − sin(2n)) / (sin n − cos n)

-(1 − 2 sin n cos n) / (sin n − cos n)

-(sin² n − 2 sin n cos n + cos² n) / (sin n − cos n)

-(sin n − cos n)² / (sin n − cos n)

-(sin n − cos n)

cos n − sin n

Limit as n approaches π/4 is 0.

7 0

3 years ago