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3 years ago

Find the midpoint of line segment

Mathematics

1 answer:

Norma-Jean [14]3 years ago

6 0

Step-by-step explanation:

$midpoint = ( \frac{4.9 + - 5.2}{2} , \: \frac{ - 1.3 + - 0.6}{2} ) \\ = ( - 0.15, \: - 0.95)$

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What is B^y=x in logarithmic form?

Gala2k [10]

Answer:

The logarithmic function for x = 2y is written as y = log2 x or f(x) = log2 x. The number 2 is still called the base. In general, y = logb x is read, “y equals log to the base b of x,” or more simply, “y equals log base b of x.” As with exponential functions, b > 0 and b ≠ 1

5 0

3 years ago

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. Use the quadratic formula to solve each quadratic real equation. Round

Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

$\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}$ , with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}$

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}$

$\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5$

So B has two solutions of 5 and -1.5.

Now to C!

$\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}$

$\frac{44}{8} = 5.5$

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

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3 years ago

A quantity with an initial value of 980 decays exponentially at a rate of 1% every 2

Firdavs [7]

Answer:

821.94

Step-by-step explanation:

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3 years ago

Use the permutation formula to solve a problem when n = 15 and r = 4.

barxatty [35]

$nPr = \frac{n!}{(n - r)!}$

$15P4 = \frac{15!}{(15 - 4)!} = \frac{15!}{11!} \\ = \frac{15 \times 14 \times 13 \times 12 \times 11!}{11!} \\ 15 \times 14 \times 13 \times 12 = 32760$

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3 years ago

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What's 367889 divided by 5789?

Dmitry_Shevchenko [17]

Answer:

63.5496631543

Step-by-step explanation:

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3 years ago

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