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Soloha48 [4]
3 years ago
7

Which equation in point slope form contains the points (-1,3) and (2,-2)

Mathematics
1 answer:
kolezko [41]3 years ago
4 0

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-1, 3) and (2, -2). Substitute:

m=\dfrac{-2-3}{2-(-1)}=\dfrac{-5}{2+1}=-\dfrac{5}{3}\\\\y-3=-\dfrac{5}{3}(x-(-1))\\\\\boxed{y-3=-\dfrac{5}{3}(x+1)}

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Simplify 1/a+b + 1/a-b + 2b/a^2-b^2​
Simora [160]

Answer:

−a^2 b^2 + 2a + 2b

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             a^2

Step-by-step explanation:

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8 0
3 years ago
Which of the following terms are like terms
prisoha [69]
The answer is B) 6xy and -16xy
4 0
3 years ago
Read 2 more answers
7b+1=-53 taking square roots
Aliun [14]
7.28 is the answer sorry if i’m wrong
6 0
3 years ago
Charlie does a weekly exercise program consisting of cardiovascular work and weight training. Each week, he exercises for at lea
german

Answer:

(x_1,y_1) = (0,9)

(x_2,y_2) = (6,3)

(x_3,y_3) = (6,12)

Step-by-step explanation:

Given

x = hours spent on cardiovascular work

y = hours spent on weight training

From the first statement,

Each week: he spends at least 9 hours

This is represented as:

Total \ge 9

x + y \ge 9

From the second statement,

Each week: he spends a max of 12 hours on weights

This is represented as:

Weight \le 12

y \le 12

From the third statement,

Each week: he spends a max of 6 hours on cardio works

This is represented as:

Cardio \le 6

x \le 6

So, the inequalities are:

x + y \ge 9

y \le 12

x \le 6

See attachment for the graph where the solution are also highlighted

From the attachment, the solutions are:

(x_1,y_1) = (0,9)

(x_2,y_2) = (6,3)

(x_3,y_3) = (6,12)

8 0
3 years ago
What are 3 consecutive integers whose product is -120
iren2701 [21]
Consecutive integers are 1 apart
x,x+1,x+2
(x)(x+1)(x+2)=-120
x^3+3x^2+3x=-120
add 120 to both sides
x^3+3x^2+3x+120=0
factor
(x+6)(x^2-3x+20)=0
set each to zero

x+6=0
x=-6

x^2-3x+20=0
will yeild non-real result, discard
x=-6
x+1=-5
x+2=-4
the numbers are -4,-5,-6



use trial and error and logic
factor 120
120=2*2*2*3*5
how can we rearange these numbers in (x)(y)(z) format such that they multiply to 120?
obviously, the 5 has to stay since 2*5=10 which is out of range
so 2*2*2*3 has to arrange to get 3,4 or 4, 6 or 6,7
obviously, 7 cannot happen since it is prime
3 and 4 results in in 12, but 2*2*2*3=24
therfor answer is 4 and 6
they are all negative since negaive cancel except 1

the numbers are -4,-5,-6
5 0
3 years ago
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