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2 years ago

I NEED HELP ASAP!!!!!!!!!!

Mathematics

1 answer:

svetoff [14.1K]2 years ago

5 0

Answer:

I know the answer

Step-by-step explanation:

x = random number then y = x + y then x = 68 So we can conclude

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Evaluate 3 to the 2nd power + (6 - 2) x 4- 6 over 3

exis [7]

Answer:

19/3 or 6.33 continuing

Step-by-step explanation:

using pemdas, do the exponent first

6-2=4

then multiply by 4

4x4 is 16

add 3^2 to this, which = 9

so 16+9-6 is on top which equals 19, this is over 3

so 19/3

4 0

3 years ago

(8p - 2) (6p+2) <br><br> help plz

qaws [65]

Answer:

$48p^2+2p-4$

Step-by-step explanation:

We can use the FOIL method to expand two multiplied binomials. It states that $(a+b)(c+d)=ac+bc+ac+bd$ . The FOIL method stands for First(first terms) outer(outer terms) inner(inner terms) last(last terms).

So, we can expand our binomials now!

$(8p-2)(6p+2)=(8p)(6p)-2(6p)+(8p)(2)-2(2)=48p^2-12p+14p-4=\boxed{48p^2+2p-4}$

8 0

3 years ago

If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly

cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_xp^x(1-p)^n-x$ , where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

$P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%$

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

7 0

3 years ago

g 78% of all Millennials drink Starbucks coffee at least once a week. Suppose a random sample of 50 Millennials will be selected

Tatiana [17]

Answer:

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

6 0

3 years ago

What is the factorization of the

astra-53 [7]

B is the correct answer. plz heart my answers, I solved multiple of your questions. I just wanna like for my answers

8 0

3 years ago

Read 2 more answers