Ask question

Ask question

All categories

3 years ago

7

a bag contains equal amounts of 10 different colored marbles. What is the chance of someone pulling out a blue marble putting it

back. then picking out another blue marble

1 answer:

worty [1.4K]3 years ago

3 0

Answer: 1/20?

Step-by-step explanation: if they’re all different colors and it’s 10 then pulling out blue has a 1/10 chance so pulling it again would be 1/20

You might be interested in

A shipment of 288 textbooks have been delivered. Each of the 10 classrooms will receive an equal share of the books, with any ex

stepan [7]

There should be 8 textbooks left in the book room

6 0

3 years ago

(-5/6x+51/2)-(2/3x+4)

stiv31 [10]

Answer:

-1.5x + 21.5 (or (43-3x)/2)

Step-by-step explanation:

(-5/6x + 51/2) - (2/3x + 4)

<em>First, find the opposite of 2/3x + 4 because of the negative sign.</em>

-5/6x + 51/2 - 4/6x - 4

<em>Now combine -5/6x and -4/6x to get -9/6x or -3/2x</em>

-3/2x + 51/2 - 4

<em>Convert 4 into 8/2 since 51/2 is a fraction.</em>

-3/2x + 51/2 - 8/2

<em>Since the denominators of 51/2 and -8/2 are the same, just subtract 51 and 8 to get 43.</em>

-3/2x + 43/2

<em>-3/2x and 43/2 have the same denominator (2), so you can just put it like this (It's up to you!):</em>

(43-3x)/2

The answer to (-5/6 + 51/2) - (2/3x + 4) is -3/2x + 43/2 (or (43-3x)/2)

<em>Or you could put it like this (I converted both -3/2 and 43/2 to a decimal.)</em>

-1.5x + 21.5

6 0

3 years ago

If a coin is tossed three times, find probability of getting

Assoli18 [71]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

‣ A coin is tossed three times.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

${\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}$

$\star \: \tt P(E)= {\underline{\boxed{\sf{\red{ \dfrac{ Favourable \: outcomes }{Total \: outcomes} }}}}}$

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes $\tt [ \: n(s) \: ]$ = 8

<u>1) Exactly 3 tails </u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: tails)} = \red{ \dfrac{1}{8}}$

<u>2) At most 2 heads</u>

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

$\therefore \sf Probability_{(at \: most \: 2 \: heads)} = \green{ \dfrac{7}{8}}$

<u>3) At least 2 tails </u>

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

$\longrightarrow \sf Probability_{(at \: least \: 2 \: tails)} = \dfrac{4}{8}$

$\therefore \sf Probability_{(at \: least \: 2 \: tails)} = \orange{\dfrac{1}{2}}$

<u>4) Exactly 2 heads </u>

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 2 \: heads)} = \pink{ \dfrac{3}{8}}$

<u>5) Exactly 3 heads</u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: heads)} = \purple{ \dfrac{1}{8}}$

$\rule{280pt}{2pt}$

8 0

2 years ago

SashulF [63]

Answer:

-3x^3 + x^2 + 4x +6

Answer is C

Step-by-step explanation:

6 0

3 years ago

What is the quotient in scientific notation?

levacccp [35]

The answer is 3.6×10^2

7 0

2 years ago