The white of the stars with the blue background is white in a blue field representing a new constellation. The blue on the flag is a primary color, kind of like the center of the attention on the flag. he blue is the first thing your eyes are drawn too.
Assuming that the letters can only be capitals or non-capitals then:
(26P2)*(9P1)*4 = 23400 possible combanations
Check the picture below.
so notice, their perimeter is the same, because the perimeter is just one rod anyway, and all rods are the same length, thus
Step-by-step explanation:
Given that,
a + 2b = 17
Also,
2a + b = 4
By adding the above expressions we get,
a + 2b + 2a + b = 17 + 4
3a + 3b = 21.
3 (a + b) = 21
a + b = 21/3
a + b = 7 Let us take 'b' = 10
a + 10 = 7
a = 7 - 10
a = -3
Now let's check by verifying by putting a = -3 and b = 10 in the previous expressions
a + 2b = 17
-3 + (2 × 10) = 17
-3 + 20 = 17
17 = 17
2a + b = 4
(2 × -3) + 10 = 4
-6 + 10 = 4
4 = 4
Therefore, a = -3 and b = 10 [(-3,10)] is the solution.
<u>ANSWER:
</u>
Zach has 28 dimes and 7 quarters.
<u>SOLUTION:
</u>
Given, Zach has 4 times as many dimes as quarters
And they have a combined value of 455 cents,
We need to find how many of each coins does he have?
Let, the number of dimes be x and number of quarters be y.
Then, x = 4y → (1)
Total combined value = 455 cents
x(value of one dime) + y(value of one quarter) = 455 cents
x(10 cents) + x(25 cents) = 455 cents
10x + 25y = 455 → (2)
Now, substitute (1) in (2)
10(4y) + 25y = 455
40x + 25y = 455
65y = 455
y = 7
substitute y value in (1)
x = 4(7) = 28
Hence, zach has 28 dimes and 7 quarters.
