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3 years ago

What is another way to make 57 cents with coins

Mathematics

1 answer:

Fed [463]3 years ago

7 0

2 quarters, 7 pennies
5 dimes, 7 pennies
10 nickels, 7 pennies

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CORRECT ANSWER GETS BRAINLYEST Drag each set of coordinates to the correct location on the table. Not all sets of coordinates wi

nata0808 [166]

Answer:

(-4,-7)

(4,7)

(-4,-5)

(1,-1)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Please help me I would really appreciate it, If you can't that is okay but please try!

jeka57 [31]

Answer:

Either A or B

Step-by-step explanation:

Its not C or D sorry I couldn't be much help, but I hope that makes it a bit easier?

8 0

2 years ago

The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room

Alexandra [31]

Answer:

$\bar x = 260.1615$

$\sigma = 70.69$

The confidence interval of standard deviation is: $53.76$ to $103.25$

Step-by-step explanation:

Given

$n =20$

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}$

$\bar x = \frac{5203.23}{20}$

$\bar x = 260.1615$

$\bar x = 260.16$

Solving (b): The standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}$ $\sigma = \sqrt{\frac{94938.80}{19}}$

$\sigma = \sqrt{4996.78}$

$\sigma = 70.69$ --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

$c =0.95$

So:

$\alpha = 1 -c$

$\alpha = 1 -0.95$

$\alpha = 0.05$

Calculate the degree of freedom (df)

$df = n -1$

$df = 20 -1$

$df = 19$

Determine the critical value at row $df = 19$ and columns $\frac{\alpha}{2}$ and $1 -\frac{\alpha}{2}$

So, we have:

$X^2_{0.025} = 32.852$ ---- at $\frac{\alpha}{2}$

$X^2_{0.975} = 8.907$ --- at $1 -\frac{\alpha}{2}$

So, the confidence interval of the standard deviation is:

$\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }$ to $\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }$

$70.69 * \sqrt{\frac{20 - 1}{32.852}$ to $70.69 * \sqrt{\frac{20 - 1}{8.907}$

$70.69 * \sqrt{\frac{19}{32.852}$ to $70.69 * \sqrt{\frac{19}{8.907}$

$53.76$ to $103.25$

8 0

2 years ago

10 Points!

Gekata [30.6K]

$a_1=6,\ a_n=2\cdot a_{n-1}\\\\a_2=2\cdot a_1\to a_2=2\cdot6=12\\\\a_3=2\cdot a_2\to a_3=2\cdot12=24\\\\a_4=2\cdot a_3\to a_4=2\cdot24=48\\\\a_5=2\cdot a_4\to a_5=2\cdot48=96\\\\a_6=2\cdot a_5\to a_6=2\cdot96=192\\\\\text{Answer:}\\D)\ 6,\ 12,\ 24,\ 48,\ 96,\ 192$

4 0

3 years ago

Haseena bought 1 pencil box, 4 pencils and 4 notebooks from a store. She paid Rs. 95 in all. Some ink fell on the bill that she

Rudik [331]

The price of the one notebook will be Rs. 10.6

Let the price of one notebook be x.

If Haseena bought 1 pencil box, 4 pencils and 4 notebooks from a store, with a total of Rs. 95 paid in all, then;

1x + 4x + 4x = 95

9x = 95

x = 95/9

x = 10. 6

Hence the price of the one notebook will be Rs. 10.6

Learn more on ratio here: brainly.com/question/20346769

8 0

2 years ago