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yaroslaw [1]
3 years ago
12

Sqrt(2x-6)=3-x Solve for x

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
5 0

Answer:

x = 3

Step-by-step explanation:

\sqrt{2x - 6}  = 3 - x

Square both sides of the equation

2x - 6 = (3 - x)^{2} = 9 - 6x + x^{2} \\

x^{2}  - 8x + 15 = 0\\

(x - 3)(x - 5) = 0

x = 3 or 5

Now, you must always check your results because a result may not satisfy the original equation.

If x = 3, then \sqrt{2x - 6} = \sqrt{2(3) - 6} = \sqrt{6 - 6}  = \sqrt{0} = 0  and 3 - x = 3 - 3 = 0

So 3 satisfies the original.

If x = 5, then \sqrt{2(5) - 6}  = \sqrt{10 - 6} = \sqrt{4} = 2,  but 3 - x = 3 - 5 = -2.  Therefore, 5 does NOT satisfy the original equation.

That means that x = 3 is the solution to the equation.

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Shani borrowed $5000 at an annual interest rate of 4% compounded yearly. William borrowed the same amount of money at an annual
Natalka [10]

Answer: William will pay $ 330.76 more interest than Shani at the end of 3 years.

Step-by-step explanation:

Compound interest = P((1+r)^t-1)<em> , </em>P= principal , r= rate of interest , t= time

Given: P = $5000 , t= 3 years

For Shani , r= 4% = 0.04

Compound interest = 5000((1+0.04)^3-1)

=5000(1.124864-1)\\\\=5000(0.124864)\\\\=\$\ 624.32

For William, r= 6%= 0.06

Compound interest = 5000((1+0.06)^3-1)

=5000(1.191016-1)\\\\=5000(0.191016)\\\\=\$\ 955.08

Difference = $ ( 955.08- 624.32)

= $ 330.76

Hence, William will pay $ 330.76 more interest than Shani at the end of 3 years.

6 0
3 years ago
Plz help me with this ASAP
VLD [36.1K]

Answer:

Step-by-step explanation:

plug all in

1) 0 when x=0

2) 1*6-1²=6-1=5

3) 6*2-2²=12-4=8

4)6*3-3²=18-9=9

5) 6*4-4²=24-16=8

6)6*5-5²=30-25=5

7) 6*6-6²=36-36=0

6 0
3 years ago
Help pleaseeee pleaseeee pleaseeee
Murljashka [212]
We have the same workbook lol
The answer is
Drums: 2/4
milks 4/9
(unless your teacher wants it improper.)
4 0
3 years ago
Which ordered pair makes both inequalities true? y &lt; 3x – 1 y &gt; –x + 4 On a coordinate plane, 2 straight lines are shown.
Katen [24]

Answer:

(4,0)

Step-by-step explanation:

we have

y< 3x-1 ----> inequality A

y \geq -x+4 ----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

Verify each ordered pair

case 1) (4,0)

<em>Inequality A</em>

0< 3(4)-1

0< 11 ----> is true

<em>Inequality B</em>

0 \geq -(4)+4

0 \geq 0 ----> is true

so

the ordered pair makes both inequalities true

case 2) (1,2)

<em>Inequality A</em>

2< 3(1)-1

2< 2 ----> is not true

so

the ordered pair not makes both inequalities true

case 3) (0,4)

<em>Inequality A</em>

4< 3(0)-1

4< -1 ----> is not true

so

the ordered pair not makes both inequalities true

case 4) (2,1)

<em>Inequality A</em>

1< 3(2)-1

1< 5 ----> is true

<em>Inequality B</em>

1 \geq -(2)+4

1 \geq 2 ----> is not true

so

the ordered pair not makes both inequalities true

5 0
3 years ago
Read 2 more answers
Please Show Your Work All My Points Please Help Me!!!!! 6x^2+8x-6=2-2x-2
Juliette [100K]

Answer:

6x^2+10x-6=0

Step-by-step explanation:

First, you need to add all like terms:

6x^2+8x-6=-2x

Now move the -2x to the other side:

6x^2+10x-6=0

7 0
3 years ago
Read 2 more answers
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