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3 years ago

What is the median of the data set given below? 26, 39, 18, 21, 24, 48, 21, 35

2 answers:

6 0

To find the Median, place the numbers you are given in value order and find the middle number. If there are two middle numbers, you average them.
18, 21, 21, 24, 26, 35, 39, 48

The two middle number are 24 and 26
Average 24 + 26/2 = 25
The median is 25

Mice21 [21]3 years ago

4 0

To get the median is put then smallest to largest then x them out one of each side at a time and get. 25

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Plz help me with this math and also explain

jasenka [17]

Step-by-step explanation:

SI = $250
Rate (R) = 12 $\sf \dfrac{1}{2}$ %
Time (t) = 4 years

$\longrightarrow \tt { SI = \dfrac{PRT}{100} } \\$

$\longrightarrow \tt { 250 = \dfrac{P \times 12\cfrac{1}{2} \times 4}{100} } \\$

$\longrightarrow \tt { 250 = \dfrac{P \times \cfrac{25}{2} \times 4}{100} } \\$

$\longrightarrow \tt { 250 = \dfrac{P \times 25 \times 2}{100} } \\$

$\longrightarrow \tt { 250 = \dfrac{P \times 50}{100} } \\$

$\longrightarrow \tt { 250 \times 100 = P \times 50} \\$

$\longrightarrow \tt { 25000 = P \times 50} \\$

$\longrightarrow \tt { \dfrac{25000}{50} = P } \\$

$\longrightarrow \underline{\boxed{ \green{ \tt { \$ \; 500 = P }}}} \\$

Therefore principal is $500.

2/7 of the balls are red.
3/5 of the balls are blue.
Rest are yellow.
Number of yellow balls = 36

Let the total number of balls be x.

→ Red balls + Blue balls + Yellow balls = Total number of balls

$\longrightarrow \tt{ \dfrac{2}{7}x + \dfrac{3}{5}x + 36 = x} \\$

$\longrightarrow \tt{ \dfrac{10x + 21x + 1260}{35} = x} \\$

$\longrightarrow \tt{ \dfrac{31x + 1260}{35} = x} \\$

$\longrightarrow \tt{ 31x + 1260= 35x} \\$

$\longrightarrow \tt{ 1260= 35x-31x} \\$

$\longrightarrow \tt{ 1260= 4x} \\$

$\longrightarrow \tt{ \dfrac{1260 }{4}= x} \\$

$\longrightarrow \underline{\boxed{ \tt { 315 = x }}} \\$

Total number of balls is 315.

A/Q,

3/5 of the balls are blue.

$\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}x} \\$

$\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}(315)} \\$

$\longrightarrow \tt{ Balls_{(Blue)} = 3(63)} \\$

$\longrightarrow \underline{\boxed{ \green {\tt { Balls_{(Blue)} = 189 }}}} \\$

8 0

3 years ago

5 and 1/4 divided by negative 6 simplify

Zanzabum

Answer:

-0.875

Step-by-step explanation:

5 1/4 = 5.25

5.25/ -6 = -0.875

8 0

3 years ago

Read 2 more answers

The scale on the architectural plans for a new house is 1 in. equals 4 ft. Find the length and width (in ft) of a room that meas

Oksi-84 [34.3K]

Answer: the actual length and width of the room is 24ft by 36ft

Step-by-step explanation:

The scale on the architectural plans for a new house is 1 in. equals 4 ft. This means that every 1 inch on the on the architectural plan represents 4 feet on the actual building.

Therefore, if the length of the room as measured on the drawing is 6 inches, the actual length of the room will be

6 × 4 = 24 feet

Also, if the width of the room as measured on the drawing is 9 inches, the actual width of the room will be

9 × 4 = 36 feet

8 0

3 years ago

If dy/dx = x(y-1), find the equation of the tangent line at x=-2 with f(-2)=3

Lapatulllka [165]

Answer:

The equation of the tangent line passing through the point (-2,3) is

4 x + y +5 =0

Step-by-step explanation:

Step(i):-

Given that the slope of the tangent

$m = \frac{dy}{dx} = x(y-1)$

m = -2( 3-1) = -4

Given point x = -2

y = f(-2) =3

∴The given point ( x₁ , y₁) = ( -2 ,3)

Step(ii):-

The equation of the tangent line passing through the point (-2,3)

$y - y_{1} = m(x-x_{1} )$

$y -3 = -4(x-(-2))$

y -3 = -4( x+2)

y-3 = -4x -8

4x + y -3+8=0

4x +y +5=0

Step(iii):-

The equation of the tangent line passing through the point (-2,3) is

4 x + y +5 =0

3 0

2 years ago

If Y has a geometric distribution with probability of success p, show that the moment-generating function for Y is

butalik [34]

Answer:

M₀ (t) = p / e^-t -q = p (e^-t -q) ^ -1

Step-by-step explanation:

Let the random variable Y have a geometric distribution g (y;p) = pq y-¹

The m.g.f of the geometric distribution is derived as below

By definition , M₀ (t) = E (e^ ty) = ∑ (e^ ty )( q ^ y-1)p ( for ∑ , y varies 1 to infinity)

= pe^t ∑(e^tq)^y-1

= pe^t/1- qe^t, where qe^t <1

In order to differentiate the m.g.f we write it as

M₀ (t) = p / e^-t -q = p (e^-t -q) ^ -1

M₀` (t) = pe^-t (e^-t -q) ^ -2 and

M₀^n(t) = 2pe^-2t (e^-t -q) ^ -3 - pe^-t (e^-t -q) ^ -2

Hence

E (y) = p (1-q)-² = 1/p

E (y²) =2 p (1-q)-³ - p (1-q)-²

= 2/p² - 1/p and

σ² = [E (y²) -E (y)]²

= 2/p² - 1/p - (1/p)²

= q/p²

5 0

3 years ago