Step-by-step explanation:
<h2>[1]</h2>
- SI = $250
- Rate (R) = 12
% - Time (t) = 4 years









Therefore principal is $500.
<h2>__________________</h2>
<h2>[2]</h2>
- 2/7 of the balls are red.
- 3/5 of the balls are blue.
- Rest are yellow.
- Number of yellow balls = 36
Let the total number of balls be x.
→ Red balls + Blue balls + Yellow balls = Total number of balls








Total number of balls is 315.
A/Q,
3/5 of the balls are blue.




Answer:
-0.875
Step-by-step explanation:
5 1/4 = 5.25
5.25/ -6 = -0.875
Answer: the actual length and width of the room is 24ft by 36ft
Step-by-step explanation:
The scale on the architectural plans for a new house is 1 in. equals 4 ft. This means that every 1 inch on the on the architectural plan represents 4 feet on the actual building.
Therefore, if the length of the room as measured on the drawing is 6 inches, the actual length of the room will be
6 × 4 = 24 feet
Also, if the width of the room as measured on the drawing is 9 inches, the actual width of the room will be
9 × 4 = 36 feet
Answer:
The equation of the tangent line passing through the point (-2,3) is
4 x + y +5 =0
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given that the slope of the tangent</em>
<em> </em>
<em></em>
<em> m = -2( 3-1) = -4</em>
<em>Given point x = -2</em>
<em> y = f(-2) =3</em>
<em>∴The given point ( x₁ , y₁) = ( -2 ,3)</em>
<u><em>Step(ii):-</em></u>
The equation of the tangent line passing through the point (-2,3)


y -3 = -4( x+2)
y-3 = -4x -8
4x + y -3+8=0
4x +y +5=0
<u><em>Step(iii):-</em></u>
<em>The equation of the tangent line passing through the point (-2,3) is</em>
<em> 4 x + y +5 =0</em>
<em></em>
Answer:
M₀ (t) = p / e^-t -q = p (e^-t -q) ^ -1
Step-by-step explanation:
Let the random variable Y have a geometric distribution g (y;p) = pq y-¹
The m.g.f of the geometric distribution is derived as below
By definition , M₀ (t) = E (e^ ty) = ∑ (e^ ty )( q ^ y-1)p ( for ∑ , y varies 1 to infinity)
= pe^t ∑(e^tq)^y-1
= pe^t/1- qe^t, where qe^t <1
In order to differentiate the m.g.f we write it as
M₀ (t) = p / e^-t -q = p (e^-t -q) ^ -1
M₀` (t) = pe^-t (e^-t -q) ^ -2 and
M₀^n(t) = 2pe^-2t (e^-t -q) ^ -3 - pe^-t (e^-t -q) ^ -2
Hence
E (y) = p (1-q)-² = 1/p
E (y²) =2 p (1-q)-³ - p (1-q)-²
= 2/p² - 1/p and
σ² = [E (y²) -E (y)]²
= 2/p² - 1/p - (1/p)²
= q/p²