Please Help!!! I give a medal to anyone to tries!!!

1 answer:

5 0

Well, the way I see it is that both Mr. Romano, and Ms. Guerra are correct but Professor McCoy is incorrect because he said (x+2) when it should be (x-2).

The factor theorem states that:
If f(a)=0, then (x-a) is a factor

The remainder theorem states that:
If (x-a) is a factor of f(x), then f(x) / (x-a) = 0

So if 2 is indeed a zero of f(x), then a factor must be (x-2) according to the fist which supports Ms. Guerra and also if (x-2) is indeed a factor as Ms. Guerra says then we know that f(x) / (x-a) = 0 which supports Mr. Romano

Professor McCoy is wrong because he used (x + 2) when it should be (x-2). I know this because according to the factor theorem if f(a)=0, then (x-a) is a factor. And the remainder theorem says if (x-a) is a factor of f(x), then f(x)/x-a =0.

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8 Leandra's fastest time for the 400 m is 70 seconds. In his next race he improves by

disa [49]

8) a) The new fastest time is 56.7 seconds, b) The <em>overall percentage</em> improvement is 19 %.

9) The height after the first increase is 1.375 meters and after the second increase is 1.54 meters.

<h3>How to apply percentages in real life applications</h3>

In this problem we have two examples from real life, in which percentages are used. The first is the distance traveled by a runner in a given time and the second is the growth of a person in time. Change in variables based on percentages are described by the following formula:

C' = C · (1 + r / 100) (1)

Where:

C - Initial value
C' - Final value
r - Percentage of change.

Now we proceed to resolve on each case. 8) a) Please notice that the runner must cover the trail in less time and percentage time must be negative. If we know that C = 70 and r = - 10, then his new fastest time is:

C' = 70 · (1 - 10 / 100)

C' = 70 · 0.90

C' = 63

And again: (C' = 63, r = - 10)

C'' = 63 · (1 - 10 / 100)

C'' = 63 · 0.90

C'' = 56.7

The new fastest time is 56.7 seconds.

b) And the overall percentage improvement is:

r = (|C'' - C| / C) × 100 %

r = (|56.7 - 70| / 70) × 100 %

r = 19 %