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aliina [53]
3 years ago
14

How do I solve these problems?

Mathematics
1 answer:
dedylja [7]3 years ago
8 0
Equation=8n+10
15th term=130
16th term=138
Below r my steps

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What is the reciprocal of -2/7
dezoksy [38]

Just flip it to find recipricol to be

-7/2

4 0
3 years ago
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Write a number sentence that illustrates the following. A number with two decimal places multiplied by a number with one decimal
Zielflug [23.3K]

Answer:

D

Step-by-step explanation:

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1. An account is opened with a balance of $2800earning 4.25% simple interest. What will be thebalance in the account in 30 years
JulijaS [17]

Answer:

$6370

Explanation:

The simple interest formula gives us the final amount A given the principal amount P:

A=P(1+rt)

where r is the interest rate and t is the time interval.

Now in our case we have

P = 2800

r = 4.25/100

t = 30 years

therefore, the above formula gives

A=2800(1+\frac{4.25}{100}\cdot30)

which simplifies to give

\boxed{A=\$6370}

Hence, the account balance after 30 years will be $6370.

7 0
1 year ago
Find an equation of the circle that satisfies the given conditions. (Give your answer in terms of x and y.) Center at the origin
Elanso [62]

Answer:

The equation of circle is x^2+y^2=65.

Step-by-step explanation:

It is given that the circle passes through the point (8,1) and center at the origin.

The distance between any point and the circle and center is called radius. it means radius of the given circle is the distance between (0,0) and (8,1).

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula the radius of circle is

r=\sqrt{\left(8-0\right)^2+\left(1-0\right)^2}=\sqrt{65}

The standard form of a circle is

(x-h)^2+(y-k)^2=r^2         .... (1)

where, (h,k) is center and r is radius.

The center of the circle is (0,0). So h=0 and k=0.

Substitute h=0, k=0 and r=\sqrt{65} in equation (1).

(x-0)^2+(y-0)^2=(\sqrt{65})^2

x^2+y^2=65

Therefore the equation of circle is x^2+y^2=65.

5 0
3 years ago
$1,000,000 Question: Answer these algebra problems
taurus [48]
What I meant was, which ones do you need and could you take a picture in better lighting? I can't see it all the way.
7 0
3 years ago
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