Angle m∠1 if formed by a tangent and secant intersecting outside of circle. The intercepted arcs are arc LK and arc JK.
Thus;
Angle formed by Tangent and secant
=1/2(DIFFERENCE of Intercepted Arcs)
m∠1=1/2(mJK-LK)
Answer: m∠1=1/2(mJK-KL)
Answer: y =2x + 1
Step-by-step explanation: just use y=mx + b to find the equation
Answer:
y = 2x - 3
Yes, your answer is correct.
Step-by-step explanation:
First, find the slope of the two points by using the slope formula:
y2 - y1
m = -------------
x2 - x1
13 - 5
m = -------------
8 - 4
8
m = ------- = 2
4
To find the y-intercept, plug in values into the slope-intercept formula:
y = mx + b
Where m = slope and b= y-intercept. Use any one of the points. I'll be using (4,5):
5 = (2) (4) + b
5 = 8 + b
-3 = b
b = -3
So, putting everything into the slope intercept formula:
y = 2x - 3
since this is a multiplication, all the numerators are just factors of the product numerator and all denominators are just factors of the product denominator, so we can simply reorder them some, without changing the product.