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2 years ago

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Monica earns $363 a week. Rachel works for $8.25 an hour. Which inequality represents how many hours must Rachel work to make as

much as or more than Monica? 8.25h > 363 8.25h = 363 8.25h > 363 8.25h < 363

1 answer:

statuscvo [17]2 years ago

8 0

Not sure but I really wish I could help

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if a number line plot starts from 2 (including the point) and extends towards positive infinity, the corresponding inequality is

murzikaleks [220]

Answer:

$2 \leqslant y \leqslant \infty$

Step-by-step explanation:

y is equal to 2 and goes up to infinity

6 0

2 years ago

A 7-pack of plastic rings costs $2.52. What is the unit price? per ring?

VikaD [51]

Answer:

7 rings = $2.52

then 1 ring will cost = 1/7×2.52

= 0.36

Therefore 1 ring will cost $0.36.

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2 years ago

A company provides a monthly pension to its employees. A person retiring at 62 retires and receives a full monthly pension. If t

IRISSAK [1]

Answer:

<em><u>The reduction is 8.6%</u></em>

Explanation:

Call F the full monthly pension of a person retiring at 62.

If a person continues to work the pension grows at a rate of 6% per year, compounded monthly, so use the compounded growing formula:

$Pension=F(1+r/12)^{12t}$

Where r = 6 / 100 = 0.06, and t = number of years after retirement.

<u>For retirement at 65.5</u>:

t = 65.5 - 62 = 3.5

$Pension=F(1+0.06/12)^{12\times 3.5}=1.233F$

<u>For retirement at 67</u>:

t = 67 - 62 = 5

$Pension=F(1+0.06/12)^{12\times 5}=1.349F$

<u>Percent reduction of people who retire at 65.5 compared to what they would receive at 67</u>:

$(1.349F-1.233F)\times 100/(1.349F)=8.6\%$

8 0

3 years ago

Andre’s school orders some new supplies for the chemistry lab. The online store shows a pack of 10 test tubes costs $4 less than

navik [9.2K]

10t = b - 4

12b+8t = $348

This is a system of equations. I’ll be solving through substitution.

In the first equation. solving for b (the easier variable to isolate) gives you:

b = 10t + 4

Substitute this into the second equation:

12(10t+4) +8t = 348

120t+48+8t = 348

128t = 300

t = 2.34375 —> round it to the nearest cent to get 2.34 dollars

b = 10t+4

b = 10(2.34)+4

b = 27.4 dollars

4 0

3 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

so

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

so

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago