Plant (A) have a higher median at 6 and the IQR is low at 3, however, Plant (B) has a lower median of 5 but High IQR of 4 so the Plant (B) is growth is high.
hopes loves.

3 0

3 years ago

Can u guys help me please

shusha [124]

Its y=3/4x+3

you can solve it

-3x+4y=12

add 3x both sides

4y=3x+12

divide 4 by both sides

y=3/4x+4

8 0

2 years ago

Read 2 more answers

Wilfred is feeding his goats. He gives 56% of the bag of feed to the goats in field A and the rest to the goats in field B. If t

krok68 [10]

Answer:

$Feeds = 11.76kg$

Step-by-step explanation:

Given

$Field\ A= 56\%$

$Field\ B= The\ rest$

$Bag = 21kg\ feed$

Required

Determine how much goats in field A, get.

To do this, we simply multiply the percentage feed received by goats in field A by the actual bags of feeds

i.e.

$Feeds = 56\% * 21kg$

Convert percentage to decimal

$Feeds = 0.56 * 21kg$

$Feeds = 11.76kg$

<em>Hence, goats in field A get 11.76kg of feeds</em>

6 0

2 years ago