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ELEN [110]
3 years ago
6

Help!!! Factor 64f - 64g + 96 to identify the equivalent expressions Choose 2 answers

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Answer:

Its a and d

Step-by-step explanation:

I did this assignment i got those answers

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Write 24 as a product of its prime factors.
Alex777 [14]
<span>prime factors are prime numbers that can be multiplied to give the number.
to find the prime factors the number is divided by the prime numbers by which the number is divisible.
                                                                               
24 / 3 = 8                                                                            
8 / 2 = 4                                                                                
4 / 2 = 2                                                                             
2 / 2 = 1                                                                                 
24 is divisible by 3 , 2 , 2 and 2.
therefore 24 written as a product of its prime factors is 24 = 2 x 2 x 2 x 3</span>
8 0
3 years ago
Read 2 more answers
Find The surface area of a cone with a radius of 7 and slant hight of 9
liubo4ka [24]

Answer:14

Step-by-step explanation:

4 0
3 years ago
Two parallel lines were cut by a transversal. Which of the following scenarios is NOT a possible result?
PolarNik [594]

Answer:

  • Option D

Step-by-step explanation:

The first three options are correct.

The last option is incorrect as same side interior angles are supplementary, so they should sum to 180° but in the given option their sum is 100°.

6 0
2 years ago
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What is x for y=mx+b
Hoochie [10]
Y and x are the variables
6 0
3 years ago
How do I solve this ?
timofeeve [1]

Answer:

\large\boxed{\{4,\ 7,\ 10\}}

Step-by-step explanation:

X\ \cup\ Y\\\text{The union of a collection of sets is the set of all elements in the collection.}\\\\X\ \cap\ Y\\\text{The intersection}\ X\cap Y\ \text{of two sets X and Y is the set that contains}\\\text{all elements of X that also belong to Y, but no other elements.}\\\\A'\\\text{When A is a subset of a given set U, the absolute complement A}\\\text{is the set of elements in U, but not in A.}

U=\{3,\ 4,\ 5,\ 6,\ 7,\ 8,\ 9,\ 10\}\\A=\{4,\ 6,\ 8\}\\B=\{3,\ 4,\ 7,\ 10\}\\C=\{3,\ 5,\ 9\}\\\\A\ \cup\ B=\{4,\ 6,\ 8\}\ \cup\ \{3,\ 4,\ 7,\ 10\}=\{3,\ 4,\ 6,\ 7,\ 8,\ 10\}\\C'=\{3,\ 4,\ 5,\ 6,\ 7,\ 8,\ 9,\ 10\}-\{3,\ 5,\ 9\}=\{4,\ 6,\ 7,\ 8,\ 10\}\\B\ \cap\ C'=\{3,\ \b4,\ \b7,\ \b1\b0\}\ \cap\ \{\b4,\ 6,\ \b7,\ 8,\ \b1\b0\}=\{\b4,\ \b7,\ \b1\b0\}\\\\(A\ \cup\ B)\ \cap\ (B\ \cap\ C')=\{3,\ \b4,\ 6,\ \b7,\ 8,\ \b1\b0\}\ \cap\ \{\b4,\ \b7,\ \b1\b0\}=\{\b4,\ \b7,\ \b1\b0\}

6 0
3 years ago
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