The answer
<span>the third rope to counterbalance Sam and Charlie is F
and vectF +vectF1 +vectF2 =vect0
let's consider axis
y'y </span>vectF = -F
vectF 1= F1cos60
vectF 2= F2cos45
-F = -F1cos60-F2co45
so F= F1cos60+F2co45= 350x0.5+400x0.7=457.84 pounds
Answer: The number of different combinations of 2 vegetables are possible = 15 .
Step-by-step explanation:
In Mathematics , the number of combinations of selecting r values out of n values = 
Given : Number of available vegetables = 6
Then, the number of different combinations of 2 vegetables are possible will be :
Hence , the number of different combinations of 2 vegetables are possible = 15 .
Answer:
0, π
Step-by-step explanation:
cos x sin x = sin x
cos x sin x - sin x = 0
sin x (cos x - 1) = 0
sin x = 0, x = 0, π
cos x - 1 = 0
cos x = 1, x = 0
So answers: 0, π
Answer:
2x + 12y + 43 ≥ 40
17x + 12y + 8z ≥ 20
14x + 6y + z ≤ 50
x ≥ 0
y ≥ 0
z ≥ 0
Step-by-step explanation:
given:
Cost Eggs = $2
Cost of edema = $5
cost of elbow Macaroni = $3
Lets eggs = x,
edamame = y
elbow macaroni = z
TC = 2x+5y+3z
Therefore;
2x + 12y + 43 ≥ 40
17x + 12y + 8z ≥ 20
14x + 6y + z ≤ 50
x ≥ 0
y ≥ 0
z ≥ 0
the first objective is to make sure the total cost is subject to the required nutritional requirements.
So the total cost function (TC) is denoted by the number of servings multiplied for each costs. Eggs cost $2, edamame $5, and macaroni $3.
The problem subjects that each meal contains at least 40g of carbohydrates (this is the condition).
to get this we need to add what each meal component adds to the total, eggs add 2g of carbs, edamame 12g, and macaroni 43g.
Same should be done for protein, we require at least 20 grams of protein, Eggs add 17g, edamame adds 12g, and macaroni adds 8g.
and lastly we don't want more than 50 grams of fat, Eggs add 14g, edamame add 6g and macaroni 1g.
Answer:
3
Step-by-step explanation:
us the formula
y1 - y2 divided by x1 - x2
=gradient
6 - 3 divided by 5 - 4 = gradient
3 = gradient
hope this helps
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