To keep the equation equal. what you do on one side should be done to the other.
Answer:
8 cm
Step-by-step explanation:
24 divided by 3
Identify the improper fraction. The improper fraction will have a higher number on top than on the bottom. For example, 7/4.Divide the top number, or numerator, by the bottom number, the denominator, to determine how many times the denominator fits into the numerator. In the 7/4 example, the denominator fits in one time, leaving three left over.Write the amount of times the denominator fits into the numerator as a whole number. In the 7/4 example, the answer is "1."Display the leftover number as a fraction on the right side of the whole number. In the 7/4 example, the answer is "3/4," since 7 divided by 4 equals 1 with a remainder of 3. The mixed number should look like this: "1 3/4."
There are an infinite number of such subsets. One of them is the set of real numbers in the interval (7, 8). Perhaps you're thinking "irrational" numbers, as opposed to "integers" or "rational" numbers.
Answer:
Matrix transformation = ![\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)
Step-by-step explanation:
Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: .
To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:
P'= ![\left[\begin{array}{ccc}-5\\-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%5C%5C-2%5Cend%7Barray%7D%5Cright%5D)
= (5,-2)
Q'= ![\left[\begin{array}{ccc}-6\\-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%5C%5C-3%5Cend%7Barray%7D%5Cright%5D)
= (6,-3)
R'= ![\left[\begin{array}{ccc}-2\\-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%5C%5C-3%5Cend%7Barray%7D%5Cright%5D)
= (2,-3)
