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4 years ago

Find the distance between the two points (0,0), (4,3)

Mathematics

1 answer:

Amiraneli [1.4K]4 years ago

4 0

Answer:

Distance between the points=5

Step-by-step explanation:

The distance between two points in coordinate geometry is measured by using the distance formula:

If we have given two points

$(x_1,y_1)\\\\(x_2,y_2)$

Distance formula= $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For (0,0) and (4,3)

Distance:

$\sqrt{(4-0)^2+(3-0)^2} \\\\\sqrt{4^2+3^2}\\\\\sqrt{16+9}\\\\\sqrt{25}$

Distance between the points=5

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lana66690 [7]

Answer:

Step-by-step explanation:

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3 years ago

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Multiply and simplify

steposvetlana [31]

That would be the cube root of (x+5)^11.

If desired, this could be reduced to the cube root of (x+5)^9*(x+5)^2, which would be

(x+5)^3*(x+5)^(2/3)

7 0

4 years ago

State the domain of the relation {(0,5), (5,2), (0, -4), (1,5)}.

Alexandra [31]

Answer:

Step-by-step explanation:

The domain of a relation is all the x-coordinates in the relation, where no x-coordinate repeats. In the relation {(0,5), (5,2), (0,-4), (1,5)}, the domain is {0, 1, 5} because those are the only x-coordinates in the points.

Therefore, the answer is B.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

8 0

3 years ago

Use signed numbers to solve. A helicopter descended 1200 feet, rose 800 feet, and then descended 450 feet. What was the net gain

DENIUS [597]

B. Lost 850 ft
800-450= 350
1200-350=850

I hope I helped :D

6 0

3 years ago

CAN SONEONE PLEASE HELP ME WITH MY MATH PLEASEEEE!!!!!

Marina86 [1]

Answer:

√190

Step-by-step explanation:

In the figure , there are 2 right angled triangles with a common perpendicular & both the triangles combine to form a new right angled triangle.

Let the triangle with 9 as base be T¹ & Let the triangle with base 10 be T². Let the triangle formed by T¹ & T² be T³.

In T² ,

Hypotenuse = y

Base = 10

According to Pythagorean Theorem ,

(Hypotenuse)² = (Base)² + (Perpendicular)²

Hence, (Perpendicular)² = $y^2 - 10^2 = y^2 - 100$

In T¹ ,

Perpendicular = $\sqrt{y^2 - 100}$ (∵ Both T¹ & T² have common perpendicular)

⇒(Perpendicular)² = $y^2 - 100$

Base = 9

⇒ (Base)² = 9²

Hypotenuse =

Using Pythagorean Theorem ,

(Hypotenuse)² = (Perpendicular)² + (Base)²

⇒ (Hypotenuse)² = $y^2 - 100 + 9^2$ .............................................eqn.2

Now in T³ ,

Base = y

⇒ (Base)² = y²

Perpendicular = $\sqrt{(y^2 - 100) + 9^2}$ (∵Perpendicular of T³ = Hypotenuse of T²)

⇒ (Perpendicular)² = $(\sqrt{(y^2 - 100) + 9^2})^2= (y^2 - 100) + 81 = y^2 - 19$

Hypotenuse = 9 + 10 = 19

Using Pythagorean Theorem ,

(Hypotenuse)² = (Perpendicular)² + (Base)²

$=> 19^2 = y^2 - 19 + y^2\\\\=> 2y^2 = 19^2 + 19 = 19(19 + 1) = 19*20\\\\=> y^2 = \frac{19*20}{2} = 19*10 = 190\\ \\=> y =\sqrt{190}$

3 0

3 years ago