Set the two equal to each other and solve for x
-2x+1 = -2x²+1
-2x= -2x²
x=x²
x²-x=0
x(x-1) =0, so x is either 0 or 1
two solutions, namely (0,1) and (1,1)
Rita = $150
Bob = $150 - $35 = $115 Bob has $115
Joe = $115 divided by 5 = $23 $23 x 4 = $92 Joe Has $92
Tim = Has $50 more then joe, $92 + $50 = $142 Tim has $142
24 inches is i am not mistaking
6 to 12 is +6
12 to 18 is +6
so 18 to 24 is +6
Answer:
The probability is 0.0052
Step-by-step explanation:
Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:
P(A/B) = P(A∩B)/P(B)
The probability P(B) that at least three are aces is the sum of the following probabilities:
- The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
- There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

So, the number of ways to select exactly 3 aces is:

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725
Then, the probability P(B) that at least three are aces is:

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:
P(A∩B) = 1/270,725
Finally, the probability P(A/B) that all four are aces given that at least three are aces is:
