3 years ago

PLEASE HELP ASAP SHOW WORK PLEASE!!!!

Mathematics

1 answer:

gregori [183]3 years ago

3 0

Answer:

The limit is -1

Step-by-step explanation:

As shown by the equation, it shows x -> -1

which represents x approaching the limit of -1

You might be interested in

In 31 days, Gwen's dog sleeps 496 jours.If she sleeps that same number of hours each night, how many hours does she sleep per ni

g100num [7]

It 496 ÷ 31 = 16 days

4 0

3 years ago

Read 2 more answers

It cost $6 to join an online DVD club and $2.50 to rent a DVD. Write an equation for the relationship that gives the total cost

Sophie [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

Use a special right triangle to find the tangent of 45°

mezya [45]

Answer:

In order to find out the tangent value of 45 degrees, we need to divide the opposite side to the angle by the adjacent side. Since both the opposite and adjacent sides of this triangle are the same, we can see that tan(45) is equal to 1.

Step-by-step explanation:

7 0

3 years ago

Henry and reiki both use 1 yard of ribbon to make bows. Write two different fractions to show that Henry and reiko use the same

SpyIntel [72]

1/1 and 5/5 hope this helps! Pls mark as brainliest answer!!!!! :)

8 0

3 years ago

Read 2 more answers

The force of the wind blowing on a vertical surface varies jointly as the area of the surface and the square of the velocity. If

Ierofanga [76]

Answer:

a force of 1250lb is exerted

Step-by-step explanation:

since the force of the wind varies jointly as the area of the surface and the square of the velocity,

let f = force

a = area

velocity =v

from the above statement, we find out that

$f \alpha a*v^2$ ----1

that is $f= k* a* v^2$ -----2

where k is a coefficent of proportionality

since velocity of wind in mph,v =50

and force in lb = 20

and surface area = $1/5 th ft^2$

from eqn 2

we have that

$20 =k*\frac{1}{5}* 50^2$

making k subject of the formula

we have that

$k =\frac{20}{\frac{1}{5} *50^2 } =\frac{1}{25} (lb.mph^-1.ft^-2)$

that means that $f =\frac{1}{25} *a *v^2$ ---3

however, when velocity = 125mph

surface area = $2ft^2$

putting values in eqn 3 we have

$f= \frac{1}{25}*2*125^2 = 1250 lb$

hence a force of 1250lb is exerted

7 0

3 years ago