1/4x is slope
3 is y-intercept
Answer:
the solutions are these
Step-by-step explanation:
![\frac{3}{14} + \frac{ \sqrt{159} }{14} i \: and \\ \: \frac{3}{14} - \frac{ \sqrt{159} }{14} i](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B14%7D%20%20%2B%20%20%5Cfrac%7B%20%5Csqrt%7B159%7D%20%7D%7B14%7D%20i%20%5C%3A%20and%20%20%5C%5C%20%5C%3A%20%5Cfrac%7B3%7D%7B14%7D%20%20%20-%20%20%5Cfrac%7B%20%5Csqrt%7B159%7D%20%7D%7B14%7D%20i)
Answer:
x=12
Step-by-step explanation:
Area of the square
A = x^2
Area of the rectangle
A = (2x-8) (x-3)
Foil
A = 2x^2 -6x -8x +24
= 2x^2 -14x+24
The areas are equal
x^2 = 2x^2 -14x+24
Subtract x^2 from each side
x^2 - x^2 = 2x^2-x^2 -14x+24
0 = x^2 -14x -24
Factor
0 = (x-12) (x-2)
Using the xero product property
x-12= 0 x-2 =0
x=12 x=2
But looking at the rectangle
x-3 is a side length
2-3 is negative so x cannot equal 2
x=12
Answer:
The predicted sales for the new set of advertising budgets is 14.
Step-by-step explanation:
The linear regression model is:
![\text{Sales}=2.9389+0.0458\cdot(\text{TV})+0.1885\cdot(\text{Radio})-0.0010\cdot(\text{Newspaper})](https://tex.z-dn.net/?f=%5Ctext%7BSales%7D%3D2.9389%2B0.0458%5Ccdot%28%5Ctext%7BTV%7D%29%2B0.1885%5Ccdot%28%5Ctext%7BRadio%7D%29-0.0010%5Ccdot%28%5Ctext%7BNewspaper%7D%29)
Compute the value of sales for:
TV = 200,
Radio = 10,
Newspaper = 20
![\text{Sales}=2.9389+0.0458\cdot(\text{TV})+0.1885\cdot(\text{Radio})-0.0010\cdot(\text{Newspaper})](https://tex.z-dn.net/?f=%5Ctext%7BSales%7D%3D2.9389%2B0.0458%5Ccdot%28%5Ctext%7BTV%7D%29%2B0.1885%5Ccdot%28%5Ctext%7BRadio%7D%29-0.0010%5Ccdot%28%5Ctext%7BNewspaper%7D%29)
![=2.9389+0.0458\cdot(200)+0.1885\cdot(10)-0.0010\cdot(20)\\=2.9389+9.16+1.885-0.0002\\=13.9837\\\approx 14](https://tex.z-dn.net/?f=%3D2.9389%2B0.0458%5Ccdot%28200%29%2B0.1885%5Ccdot%2810%29-0.0010%5Ccdot%2820%29%5C%5C%3D2.9389%2B9.16%2B1.885-0.0002%5C%5C%3D13.9837%5C%5C%5Capprox%2014)
Thus, the predicted sales for the new set of advertising budgets is 14.
Answer:
Its a no solution problem.