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marshall27 [118]
2 years ago
6

If Dorie devotes the same number of hours to studying for these three classes each week, what is the total number of hours Kathl

een will study over a three week period?

Mathematics
1 answer:
expeople1 [14]2 years ago
4 0

Answer:

The answer is 17.2 hours

Step-by-step explanation: Because first you add all hours together (which is 86/15) then multiple it by 3 (week) which is 86/5 = 17.2 hours

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The hypotenuse of a right triangle is 34 inches. One leg of the triangle is 14 inches less than the other leg. In simplified for
Karolina [17]
You can use the equation

{(x + 14)}^{2}  +  {x}^{2}  =  {34}^{2}
to find the lenth of the legs

x = leg 1
x + 14 = leg 2
6 0
3 years ago
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I need help simplifying 8^3
Dafna1 [17]
8^3 = 512
8^3 also eqauls 8 x 8 x 8. 
I hope I helped!
6 0
3 years ago
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If <3 and <4 are vertical angles and m<3=9x+5 and m<4=5x+33 find <4
KatRina [158]

Answer:

<em>68 degrees</em>

Step-by-step explanation

If <3 and <4 are vertical angles, then <3 = <4

This means that

9x + 5 = 5x + 33

9x - 5x  = 33 - 5

4x = 28

x = 28/4

x = 7

Since <4 = 5x+ 33

<4 = 5(7) + 33

<4 = 35 + 33

<4 = 68 degrees

<em>Hence the measure of <4 is 68 degrees</em>

6 0
3 years ago
Which is the correct answer?
patriot [66]
I think the answer is B
7 0
3 years ago
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
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