1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bad White [126]
3 years ago
12

7m + 3mn when m = 8 and n = 14

Mathematics
2 answers:
Kazeer [188]3 years ago
8 0

Answer:

392

Step-by-step explanation:

m = 8 and n = 14

Substituting the values of m and n in the question, we get :

7m + 3mn

=( 7 x 8) +(3 x 8 x 14)

= 56 + 336

= 392

OleMash [197]3 years ago
7 0

Answer:

356

Step-by-step explanation:

7x8+56

3x8=24

24x14=336

Add everything up

You might be interested in
Colin buys a tv for £530. It depreciates at a rate of 3% per year. How much will it be worth in 5 years? Give your answer to the
rodikova [14]

Answer: In 5 years it will be worth £455

Step-by-step explanation:

Step 1

Given

The cost of the T.V. for Colin = £530.

The rate of depreciation per year = 3%

Time/ period = 5 years

Formulae to be used

F = P  X (1 - r) ^ n

where

F = the future value after depreciation

P = the present value.

r =the interest rate per time period

n = the time/ periods

Step 2--- SOLVING

F = P  X (1- r) ^ n

F= 530 x (1-0.03) ^ 5

=530 x 0.858734

=£455.129

Rounding up to the nearest penny where appropriate = £455

3 0
3 years ago
Fill in the table using this function rule. y= -6x+1
Eddi Din [679]
Take a picture of the table
6 0
3 years ago
Evelyn and Meredith decided to kayak 1 mile up and then back in the Humboldt channel.
Yakvenalex [24]

The rate of the water flowing in the channel was 2 miles per hour, the rate Evelyn and Meredith were paddling is mathematically given as

v+ = 2.29 1mile/hour

<h3>What is the rate Evelyn and Meredith were paddling?</h3>

Generally, the equation for the up and downstream motion is mathematically given as

vup=v-2

vdown=v+2

Therefore, Statement interpretation

2/3=40*1/60

3+2/3hr=11/3

Where, tup+tdown=11/3

tup+tdown=11/3

1/Vup+1/vdown=11/3

Considering the LCD equation

3(v-2)(V+2)

Hence

\frac{3(v-2)(v+2)}{v-2}+\frac{3(v-2)(v+2)}{v+2}=\frac{11(3)(v-2)(v+2)}{3}\\\\3(v+2)+3(v-2)=11(v+2)(v-2)

11v^2-6v-44=0

v=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Resolving using the equation we have

v+ = 2.29 1mile/hour

v- = -1.745 mile hour

Read more about  Speed

brainly.com/question/4931057

#SPJ1

7 0
2 years ago
What digit is in the ten thousands place 1.03098 show how you got this and I will mark brainiest
Luden [163]
The 0 is in the ten thousands
3 0
3 years ago
Hard math question!
luda_lava [24]
First, let me show you some notation.

To show a matrix is an inverse of another matrix, we write A^{-1}

-1 is not an exponent. It just shows that a matrix is an inverse of another matrix.

For a 2x2 matrix, we can get the inverse by first making b and c negatives and swap the positions of a and d.

Then multiply each entry in the matrix by 1 divided by the determinant.

\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]^{-1} = &#10;  \frac{1}{ad - bc}\left[\begin{array}{ccc}d&{-b}\\{-c}&a\end{array}\right] =  \\  \\ \\ \left[\begin{array}{ccc}d(\frac{1}{ad-bc})&{-b}(\frac{1}{ad-bc}) \\ {-c}(\frac{1}{ad-bc}) &a(\frac{1}{ad-bc}) \end{array}\right]

I hope this helped!
8 0
3 years ago
Other questions:
  • Gradient of f(x) equal to3x^2 -2x plus 1​
    7·1 answer
  • Need help with graphing
    10·1 answer
  • What is the area of the shaded region ​
    9·1 answer
  • Graph the function: y=(x-1)^2+3. how is the graph a translation of f(x)=x^2?
    11·1 answer
  • What is one twelfth as a percentage
    5·1 answer
  • -2(6+s) Greater than or equal to -15 - 2s
    11·1 answer
  • Find the value of x (circles)
    13·2 answers
  • Two numbers that multiply to 16 and add to negative 8
    14·1 answer
  • The missing number in the arithmetic sequence: 20,
    13·1 answer
  • How much money did you save if the original price was $21 and this discount was 28%
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!