Answer:
Let B = the weight of box B
Let 2B = the weight of box A
Let 2B + 30 = the weight of box C
B + 2B + 2B + 30 = 640
5B = 610
B = 122 pounds, weight of box B
2B = 2(122) = 244 pounds, weight of box A
2B + 30 = 2(122) + 30 = 274 pounds, weight of box C
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Tan(29°) = opposite/adjacent = AC/CB ⇒
CB = AC/tan(29°) = 20/0.5543 ≈ 36.08
sin(29°) = opposite/hypotenuse = AC/AB ⇒
AB = AC/sin(29°) = 20/0.4848 ≈ 41.25
∠A = 180 - ∠B - ∠С = 180 - 29 - 90 = 61°
Answer:
D.
D is the answer because if you complete the problem it does not equal out
Answer:
Step-by-step explanation:
1)4(20+3)
2)4(20+22)
3)6.40+6.5
4)12(2+7)
