Hey there!!
Let's take the first number an the smallest number as ' x '
Then, the second consecutive even integer would become ' x + 2 '
Third integer ' x + 4 '
Hence, adding them up, we get,
x + x + 2 + x + 4
... 3x + 6
This is equal to 4 times the smallest number.
We got the smallest number as ' x '
Hence, the final equation :
... 3x + 6 = 4x
Hope my answer helps!!
Answer:
y=x^2+6
you need to add in the exponent
1/3=0.33333333 forever
2/3=0.66666666 forever
8/3=3/3+3/3+2/3=1+1+2/3=2+2/3=2+0.66666666=2.666666666666666 forever
Answer:
f(2+h)=-(h+2/3)^2+1/4
f(x+h)=-(x+h-1/2)^2+1/4
Step-by-step explanation:
1. f(2+h)=(2+h)-(2+h)^2=2+h-4-4h-h^2=-h^2-3h-2=-(h^2+3h+2)
=-(h+2/3)^2+1/4
2. Let (x+h)=a, then rewrite the equation into f(a)=a-a^2.
a-a^2=-(a^2-a)=-[(a-1/2)^2-1/4]=-(a-1/2)^2+1/4.
Insert a=x+h, f(x+h)=-(x+h-1/2)^2+1/4
