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Tomtit [17]
2 years ago
11

Hola me ayudan ???????????

Mathematics
1 answer:
prisoha [69]2 years ago
3 0

Answer:

AAAAAA

Step-by-step explanation:

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Allan paid $340 to have his car fixed at an auto-repair shop.
Gala2k [10]

Answer:

5 Hours

Step-by-step explanation:

340 = 215 + 25x

DO INVERSE OPERATIONS ~ MINUS BOTH SIDES OF THE = SIGN

340 - 215 = 125

215 - 215 = 0

125 = 25x

DIVIDE BOTH SIDE NOW

125 / 25 = 5

25x / 25 = 1 = x

<em>5 Hours</em>

3 0
3 years ago
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Jennifer's saving to buy a bike. The bike costs $245. She has $125 saved, and each week she adds $15 to her savings. How long wi
Novosadov [1.4K]
It will take her 8 weeks to save up enough money for the bike.

To get the answer first you have to subtract 125 from 245 to see how much money she still has to save then divide the answer which is 120 by 15 and you get 8. Hope this helps!!
4 0
3 years ago
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Write the slope intercept 4x-y=1
Sergio [31]

Answer:

y = 4x - 1

Step-by-step explanation:

8 0
3 years ago
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The mean consumption of water per household in a city was 1425 cubic feet per month. Due to a water shortage because of a drough
liberstina [14]

Answer:

a)t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

b) For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

Step-by-step explanation:

Information given

\bar X=1175 represent the sample mean for the cubic feets of households

\sigma=250 represent the population standard deviation

n=100 sample size  

\mu_o =1425 represent the value to verify

\alpha=0.025 represent the significance level

t would represent the statistic

p_v represent the p value

Part a

We want to test that the mean consumption of water per household has decreased due to the campaign by the city council, the system of hypothesis would be:  

Null hypothesis:\mu \geq 1425  

Alternative hypothesis:\mu < 1425  

Since we don't know the deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic is given by:

t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

Part b

For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

6 0
3 years ago
d)An insurance company will only sell its Select policy to people for whom the probability of a stroke in the next 10 years is l
NARA [144]

Answer:

Check the explanation

Step-by-step explanation:

The First action is to enter the data in Excel and then save it as a csv file. Then call the data set in R using your saved path,  I have made use of my computer path here in my code. please change it for yours.

Here is the code That you need to use for finding the multiple limear regression model and summary of it.

code:

data=read. csv("C:\\Users\\HP\\Desktop\\chegg. csv")

data

attach(data)

model=lm(Risk~Age+Blood.Pressure+Smoker)

summary(model)

And Here is the output:

Call:

lm(formula = Risk ~ Age + Blood.Pressure + Smoker)

Residuals:

Min 1Q Median 3Q Max

-13.1064 -1.5715 0.4225 3.4855 8.5561

Coefficients:

Estimate Std. Error t value Pr(>|t|)    

(Intercept) -91.75950 15.22276 -6.028 1.76e-05 ***

Age 1.07674 0.16596 6.488 7.49e-06 ***

Blood.Pressure 0.25181 0.04523 5.568 4.24e-05 ***

Smoker 8.73987 3.00082 2.912 0.0102 *  

---

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 5.757 on 16 degrees of freedom

Multiple R-squared: 0.8735, Adjusted R-squared: 0.8498

F-statistic: 36.82 on 3 and 16 DF, p-value: 2.064e-07

The answer is now written in the notebook which i am uploading..

6 0
3 years ago
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