We can use quadratic formula to determine the roots of the given quadratic equation.
The quadratic formula is:
![x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B-b%2B-%20%5Csqrt%7B%20b%5E%7B2%7D%20-4ac%7D%20%7D%7B2a%7D%20)
b = coefficient of x term = 12
a = coefficient of squared term = 4
c = constant term = 9
Using the values, we get:
So, the correct answer to this question is option B
Answer:
(p ⋅ 10) − (p ⋅ 2)
Step-by-step explanation:
Try to substitute "p" with any number.
Let's say p = 2
So
p ⋅ (10 − 2)
2 ⋅ (10 − 2)
2 ⋅ (8)
= 16
Now for the other equations
(p ⋅ 10) − (p ⋅ 2)
(2 ⋅ 10) − (2 ⋅ 2)
(20) - (4)
= 16
(10 ⋅ 2) − p
(10 ⋅ 2) − 2
(20 ) − 2
= 18
10 ⋅ 2 − p
10 ⋅ 2 − 2
20 - 2
= 18
(10 ⋅ 2) ⋅ p
(10 ⋅ 2) ⋅ 2
(20) ⋅ 2
= 40
Only (p ⋅ 10) − (p ⋅ 2) has the same result as p ⋅ (10 − 2).
Cheers
Answer:
9
Step-by-step explanation:
![\sqrt{81} = 9](https://tex.z-dn.net/?f=%20%5Csqrt%7B81%7D%20%20%3D%209)
Answer:
v= 904.78
Step-by-step explanation:
Answer:
The interest earned on the account is <u>$189.12</u>
Step-by-step explanation:
To find the overall amount after 10 years, you need to turn the 1.7% increase into a multiplier, which is 1.017. You would then put this to the power of 10, as it is after 10 years
$1030 x 1.017^10 = $1219.12
To find only the interest earned, you need to take the original balance ($1030) from the balance after 10 years ($1219.12)
$1219.12 - $1030 = <u>$189.12</u>