2 years ago

Please:)...............

Mathematics

2 answers:

Assoli18 [71]2 years ago

4 0

Answer:

F. 10 30. please brainliest

murzikaleks [220]2 years ago

4 0

Answer:

I think its H

Step-by-step explanation:

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Which equation shows that the Pythagorean identity is true for 0=270 degrees. select the equation that is in the form sin^2 0+co

Andru [333]

Answer:

c. (-1)²+0²=1

hope it is helpful to you.

5 0

2 years ago

V²=u²+2as make u as the subject

yKpoI14uk [10]

Answer:

u as the subject of the given formula is, $u = \sqrt{v^{2}-2as }$

Step-by-step explanation:

Given;

v² = u²+2as

To make u the subject of the formula, the following steps are taken;

v² = u²+2as

v² - 2as = u²

take the square - root of both sides of the equation;

$\sqrt{u^{2} } = \sqrt{v^{2}-2as } \\\\u = \sqrt{v^{2}-2as }$

Thus, u as the subject of the given formula is, $u = \sqrt{v^{2}-2as }$

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2 years ago

Create a proportional ratio to the given ratio. 10 5

stich3 [128]

Answer:

10:5 can be simplified both numbers are divisible by 5

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Step-by-step explanation:

8 0

2 years ago

247 + 794 is the same as ? + 800

Dmitry [639]

241 + 800 = 1041
247 + 794 = 1041

5 0

3 years ago

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Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

5 0

2 years ago

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