All categories

2 years ago

A car travels 30 1/5 miles in 2/3 of an hour. What is the average speed of the cat in mph?

Mathematics

2 answers:

Goshia [24]2 years ago

8 0

It’s gonna be 45.3 mph your welcome

____ [38]2 years ago

7 0

Answer:

45.3 miles/h

let 'x' be the speed of the car. Hope this will helps:)

Step-by-step explanation:

You might be interested in

Name the multiplication property shown the equation 12 times m = m times 12

Naya [18.7K]

Commutative property of multiplication

3 0

3 years ago

3.467 rounded to the nearest tenth of an ounce

kicyunya [14]

The 4 is in the tenth place...so you have to look at the number beside it to see if you round up or down. It's a 6, which is greater than 5 so you round up.

3.5

6 0

3 years ago

Simplify the following radical square root of 45 times the power of 5

Alja [10]

The answer is 13584.1129633 which simplified is 13584 :)

7 0

3 years ago

Please help me with the below question.

tresset_1 [31]

We have the following three conclusions about the piecewise function evaluated at x = 14.75:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

<h3>How to determinate the limit in a piecewise function</h3>

In a piecewise function, the limit for a given value exists when the two lateral limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.

According to the definition of lateral limit and by observing carefully the figure, we have the following conclusions:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

To learn more on piecewise function: brainly.com/question/12561612

#SPJ1

8 0

1 year ago

Identify the radical expression 61/4

d1i1m1o1n [39]

It is 24 its been a while since ive done this

6 0

2 years ago

Read 2 more answers