An expression is given in the box.
1 answer:
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Answer:
Step-by-step explanation:
We know that:
Only employees are hired during the first 3 days of the week with equal probability.
2 employees are selected at random.
So:
A. The probability that an employee has been hired on a Monday is:
.
If we call P(A) the probability that 2 employees have been hired on a Monday, then:
B. We now look for the probability that two selected employees have been hired on the same day of the week.
The probability that both are hired on a Monday, for example, we know is . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.
So
.
C. If the probability that two people have been hired on a specific day of the week is , then the probability that 7 people have been hired on the same day is:
D. The probability is . This number is quite close to zero. Therefore it is an unlikely bastate event.
Answer:
The correct options are;
Answer to A1 is D
Answer to A2 is D
Answer to A3 is D
Answer to A4 is D
Answer to A5 is D
Answer to A6 is D
Answer to A7 is D
Answer to A8 is D
Answer to A9 is D
Answer to B1 is I
Answer to B2 is I
Answer to B3 is I
Answer to B4 is I
Answer to B5 is I
Answer to B6 is I
Step-by-step explanation:
The given function is f(x) = 9·x² + 54·x - 66
The extremum of the function are found as follows;
d(f(x))/dx = 0 = d(9·x² + 54·x - 66)/dx = 18·x + 54
∴ 18·x + 54 = 0 at the maximum or minimum points
x = -54/18 = -3
Given that d²(f(x))/dx² = 18 > 0. x = -3 is a minimum point
Given that the function is a quadratic function, we have;
1) Points to the left of x = -3 are decreasing
2) Points to the right of x = -3 are increasing.
