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Yuri [45]
2 years ago
9

If p =-2 ,q= -1 and r=3 find the value of . -(1), p ²+ q²- r²​

Mathematics
1 answer:
sammy [17]2 years ago
8 0

Answer:

Step-by-step explanation:

(-2)^{2} + (-1)^{2} - (3^{2} )\\4 + 1 -9\\-4

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I really need help <br> it’s very hard
barxatty [35]

Answer:

The angle ZLK has a value of 75 degrees.

Step-by-step explanation:

We can calculate this as:

m\angle MLZ+m\angle ZLK=m\angle MLK\\\\(x+66)+(x+86)=130\\\\2x+152=130\\\\2x=130-152\\\\x=-22/2=-11\\\\\\m\angle ZLK=x+86=-11+86=75

We replace the angles values in the equation, as both angles that are formed with Z (MLZ and ZLK), when added, gives as the angle MLK. This allows us to calculate x. The value for x is -11.

Then, with the value for x we can calculate any of both angles.

6 0
3 years ago
7. Subtract the polynomials:<br> 5x2 + 4x + 1 and x2 + 3x - 4
Colt1911 [192]

Answer:

4x²+x+5.

Step-by-step explanation:

5x²+4x+1-(X²+3x-4).

5x²+4x+1-x²-3x+4.

5x²-x²+4x-3x+1+4.

4x²+x+5.

3 0
3 years ago
Read 2 more answers
Solve the following problem.<br><br> 9/11+3/4=
Liono4ka [1.6K]

Answer:

Exact form: 69/45

Decimal form: 1.5681 **repeating**

Mixed Number form: 1 25/44

Step-by-step explanation:

Brainliest please

3 0
2 years ago
Read 2 more answers
A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
bonufazy [111]

Answer:

A(t) = 300 -260e^(-t/50)

Step-by-step explanation:

The rate of change of A(t) is ...

A'(t) = 6 -6/300·A(t)

Rewriting, we have ...

A'(t) +(1/50)A(t) = 6

This has solution ...

A(t) = p + qe^-(t/50)

We need to find the values of p and q. Using the differential equation, we ahve ...

A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50

0 = 6 -p/50

p = 300

From the initial condition, ...

A(0) = 300 +q = 40

q = -260

So, the complete solution is ...

A(t) = 300 -260e^(-t/50)

___

The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.

6 0
2 years ago
Read 2 more answers
Graph the image of rhombus EFGH after a reflection across the line x = 3
igomit [66]

Answer:  see image

<u>Step-by-step explanation:</u>

Draw line x = 3.  Count how many units each point is away from line x = 3. Plot the new point the same number of units away from line x = 3 but in the opposite direction.

Point G is 4 units to the left of x = 3. The new point G' is 4 units to the right of x = 3.

Point F is 7 units to the left of x = 3. The new point G' is 7 units to the right of x = 3.

Point E is 7 units to the left of x = 3. The new point G' is 7 units to the right of x = 3.

Point H is 4 units to the left of x = 3. The new point G' is 4 units to the right of x = 3.

8 0
3 years ago
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