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Wittaler [7]
2 years ago
12

What is the volume, in cubic inches, of a cone that has a radius of 8 inches and a height of 12 inches? Use 3.14 for π , and rou

nd to the nearest hundredth. if you answer this WITH NO LINK I will give extra points!
Mathematics
1 answer:
Doss [256]2 years ago
8 0

Answer:

803.84 in^3

Step-by-step explanation:

First of all we have to find the base area

base area = radius^2 x 3.14 = 8^2 x 3.14 = 64 x 3.14 = 200,96 in^2

the volume can be find with this formula:

V = (base area x height)/3

V = (200.96 x 12)/3 = 803.84 in^3

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Answer:

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In the inequality -n < x < n, find a value for n that has no solutions.
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3 years ago
(9x+2)(4x^2+35x-9)=0
pychu [463]
(9x+2)*(4x^2+35x-9)=0

we can make this...

9x+2=0

and

4x^2+35x-9=0

then...

9x+2=0

\boxed{x=-\frac{2}{9}}


4x^2+35x-9=0

x=\frac{-b\pm\sqrt{b^2-4*a*c}}{2*a}

x=\frac{-35\pm\sqrt{35^2-4*4*(-9)}}{2*4}

x=\frac{-35\pm\sqrt{1369}}{8}

x=\frac{-35\pm37}{8}

x_1=\frac{-35+37}{8}=\frac{1}{4}

x_2=\frac{-35-37}{8}=-9

\boxed{\boxed{S=\{\frac{1}{4},-\frac{2}{9},-9\}}}

I'm sure about my answer, don't matter the order...
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