Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer: C im pretty sure
Step-by-step explanation:
Use this link it explains it pretty well
https://www.calculatorsoup.com/calculators/math/mixednumbers.php
Just copy and paste the link
Answer:
2x(power of two)+7x+5
-------------over-------------------
6x(power of two) -3x
Step-by-step explanation:
Answer:
The correct answer is option D. 48
Step-by-step explanation:
From the figure we can see that, some right angled triangles.
<u>To find the measure of LP</u>
Consider the right angled triangle LPT,
LT is the hypotenuse, LP = 50 units (given)
PT = QT = RT = 14 units
From figure we get,
LP² + PT² = LT²²
LP² = LT² - PT²
= 50² - 14²
= 2500 - 196
= 2304
LP =√2304
= 48
The correct answer is option D. 48
