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jeka94
2 years ago
9

The science teacher has a 1. 200 scale model of the space shuttle

Mathematics
1 answer:
bezimeni [28]2 years ago
5 0

I have no clue actually this is weird

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Answer:

12/3=4

Y= Time and X=The number of shoelaces

6 0
3 years ago
Read 2 more answers
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
Examine the summary section of the monthly credit card statement below. Use the first five entries to determine whether the new
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4 0
2 years ago
1.5.PS-21
dybincka [34]

Answer:

Increase in the length of one side = 3.8 ft

Step-by-step explanation:

Yossi has garage whose area is 280 ft²

After rebuilt their is increment in area by 50%

New Area = 280 × 150% = 420 ft²

Also we know that Area of Square = (Length) × (Length)

⇒ Length of Newly built garage = √420 = 20.5 ft

and Length of Originally garage = √280 = 16.7 ft

⇒ Increase in the length of one side = 20.5 - 16.7 = 3.8 ft

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3 years ago
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worty [1.4K]

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