Fron the table given:
A3 = 112,
A8 = - 3,584
An = A1 *r ^ (n-1)
=> A3 = A1 (r^2) = 112
A8 = A1(r^7) = - 3,584
=> - 3584 / 112 = (r^7) / (r^2)
=> (r^5) = - 32
=> r = - 2
=> A1 (- 2)^2 = 112
=> A1 = 112 / 4 = 28
Answer: a1 = 28
-4(2y)+11y=15, -8y+11y=3y=15: y=5
X=2(5)=10
To check your work -4(10)+11(5)=15
15=15
The diagonal of a rhombus divides it into two congruent isosceles triangles.
So ∠CBD ≅ ∠CDB
∠CBD + ∠CDB + 68 = 180
2∠CBD = 180 - 68 = 112
∠CBD = 56
We also have
∠BDE + ∠E + ∠DBE = 180
∠DBE = 180 - 73 - 36 = 71
∠EBC = ∠EBD - ∠CBD = 71 - 56 = 15
Answer: ∠EBC = 15 degrees
Answer:
W (3 , 4) or W (3 . -4)
Step-by-step explanation:
W (3 , y), origin (0 ,0)
WO = √(3-0)²+(y-0)² = √9+y²
WO = 5
√9+y² = 5
9+y² = 25
y² = 16
y = ± 4
W (3 , 4) or W (3 . -4)
Answer:
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Step-by-step explanation: