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KiRa [710]
3 years ago
14

Solve the quation by completing the square . round to the nearest hundredth if nessarsy x2-x-7=0

Mathematics
1 answer:
Anestetic [448]3 years ago
6 0

Answer:

3.19

Step-by-step explanation:

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V_F=\frac{343}{3}\pi+294\pi=\frac{343}{3}\pi+\frac{294\cdot3}{3}\pi=\frac{343}{3}\pi+\frac{882}{3}\pi=\boxed{\frac{1225}{3}\pi\ (ft^3)}\\\\\approx\frac{1225}{3}\cdot3.14}=\frac{3846.5}{3}\approx\boxed{1,282.17\ (ft^3)}\leftarrow answer
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Hank is painting his grandfather's fence. He painted 40 linear feet in 85 minutes. He still has 360 linear feet to paint. His co
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The correct answer for the question that is being presented above is this one: "C) 1.6." Hank is painting his grandfather's fence. He painted 40 linear feet in 85 minutes. He still has 360 linear feet to paint. His cousins, Sam and Alex, come <span>to help. Sam paints twice as fast and Alex paints half as fast as Hank. The constant of proportionality that relates the current fence painting rate is 1.6.</span>
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Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer. How many imaginary r
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Answer:

<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>

Step-by-step explanation:

Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:

<h3>To find how many imaginary roots does the polynomial have :</h3>
  • Since the degree of given polynomial is 4
  • Therefore it must have four roots.
  • Already given that the given polynomial has 1 positive real root and 1 negative real root .
  • Every polynomial with degree greater than 1  has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>

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