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gayaneshka [121]
3 years ago
5

Testbank, Question 095 What is the expected major organic product from the treatment of 4-methyl-2-pentyne with excess hydrogen

in the presence of a platinum catalyst
Chemistry
1 answer:
Sedbober [7]3 years ago
8 0

Answer:

See explanation and image attached

Explanation:

The addition of excess hydrogen to alkyne in the presence of a platinum catalyst leads to complete hydrogenation of the alkyne as shown in the image attached.

Therefore, an alkane is obtained as the major organic product when excess hydrogen reacts with an alkyne in the presence of a platinum catalyst.

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WILL MARK BRAINLIST
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Answer:

The average speed must be 30mph so this means the car traveled for 2hrs 60/30

7 0
3 years ago
How many electrons make up a charge of -50.0 μc ? Express your answer using three significant figures?
SVETLANKA909090 [29]

The charge on one mole of electrons = 96485 C =  1 Faraday

so if charge is 96485 C the moles of electrons are 1 = 6.023 X 10^23 electrons

if charge is 1 C the number of electrons = 6.023 X 10^23 / 96485

If charge is 50 micro C the number of electrons

              = 6.023 X 10^23 X 50 X 10^-6 / 96485

             = 3.12 X 10^14 electrons


5 0
3 years ago
Read 2 more answers
Which of the following statements is not true about the object moving with constant speed?
natali 33 [55]

Answer: B The speed of the object is equal to zero

Explanation:

8 0
3 years ago
Aqueous solutions of ammonium iodide and lead (II) nitrate are mixed. Precipitate:
Tomtit [17]

Chemical equation:

Pb(NO3)2(aq) + 2NH4I(aq) -->PbI2(s) + 2NH4NO3(aq)

Precipitate:

PbI2 (because it's a yellow insoluble solid)

Complete Ionic Equation:

Pb(aq) + 2NO3(aq) + 2NH4(aq) + I2(aq) --> Pb(s) + I2(s) + 2NH4(aq) + 2NO3(aq)

Net ionic equation:

Pb(aq) + I2(aq) --> Pb(s) + I2(s)

Let me know if there are any errors. Goodluck :)

4 0
3 years ago
Calculate the concentration of H3O+ in a solution that contains 5.5 × 10-5 M OH- at 25°C. Identify the solution as acidic, basic
k0ka [10]

Explanation:

To calculate [H3O+] in the solution we must first find the pH from the [ OH-]

That's

pH + pOH = 14

pH = 14 - pOH

To calculate the pOH we use the formula

pOH = - log [OH-]

And [OH-] = 5.5 × 10^-5 M

So we have

pOH = - log 5.5 × 10^ - 5

pOH = 4.26

Since we've found the pOH we can now find the pH

That's

pH = 14 - 4.26

pH = 9.74

Now we can find the concentration of H3O+ in the solution using the formula

pH = - log H3O+

9.74 = - log H3O+

Find the antilog of both sides

<h2> H3O+ = 1.8 × 10^ - 10 M</h2>

The solution is basic since it's pH lies in the basic region.

Hope this helps you

4 0
4 years ago
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