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2 years ago

Please solve! Thanks

Chemistry

1 answer:

WARRIOR [948]2 years ago

7 0

Answer:

Oxygen needed for Stannous Oxide: 1.350g

Oxygen needed for Stannic Oxide: 2.710g

Explanation:

You're working with 10.00 grams of Tin mass for both Stannous Oxide and Stannic Oxide.

- 10.00 grams of Tin for Stannous Oxide is already 88.10% of the mass needed. You need to find how much 11.90% of Oxygen mass is needed to create the compound. Find a factor that you can multiply 88.10% by to get 100%

- 88.10 * x = 100

- Solve for x and you get 1.135

- Multiply that number by the mass of Tin (10.00 grams) to get the complete compound (Mixture of Tin and Oxygen).

- 10.00g * 1.135 = 11.35g (Tin + Oxygen)

- Subtract (Compound - Tin) to find Oxygen

- 11.35g - 10.00g = 1.350g (Oxygen)

Repeat the process with Stannic Oxide

- Find the factor that gets 78.70% to 100%

- 100/78.70 = 1.271

- Multiply by Tin mass

- 10.00g * 1.271 = 12.71g (Compound)

- Subtract Compound by Tin

- 12.71g - 10.00g = 2.710g (Oxygen)

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3 years ago

Read 2 more answers

Starting with 2.50 mol of N2 gas (assumed to be ideal) in a cylinder at 1.00 atm and 20.0C, a chemist first heats the gas at con

arsen [322]

Answer:

a) $T_b=590.775k$

b) $W_t=1.08*10^4J$

d) $Q=3.778*10^4J$

d) $\triangle V=4.058*10^4J$

Explanation:

From the question we are told that:

Moles of N2 $n=2.50$

Atmospheric pressure $P=100atm$

Temperature $t=20 \textdegree C$

$t = 20+273$

$t = 293k$

Initial heat $Q=1.36 * 10^4 J$

Generally the equation for change in temperature is mathematically given by

$\triangle T=\frac{Q}{N*C_v}$

Where

$C_v=Heat\ Capacity \approx 20.76 J/mol/K$

$T_b-T_a=\frac{1.36 * 10^4 J}{2.5*20.76 }$

$T_b-293k=297.775$

$T_b=590.775k$

Generally the equation for ideal gas is mathematically given by

$PV=nRT$

For v double

$T_c=2*590.775k$

$T_c=1181.55k$

Therefore

$PV=Wbc$

$Wbc=(2.20)(8.314)(1181_590.778)$

$Wbc=10805.7J$

Total Work-done $W_t$

$W_t=Wab+Wbc$

$W_t=0+1.08*10^4$

$W_t=1.08*10^4J$

Generally the equation for amount of heat added is mathematically given by

$Q=nC_p\triangle T$

$Q=2.20*2907*(1181.55-590.775)\\$

$Q=3.778*10^4J$

Generally the equation for change in internal energy of the gas is mathematically given by

$\triangle V=nC_v \triangle T$

$\triangle V=2.20*20.76*(1181.55-293)k$

$\triangle V=4.058*10^4J$

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3 years ago

Calculate the pH if the [H+} = 0.0030 M

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Answer: ph = 2.523

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3 years ago

Consider 2 Al + 6 HCl → 2 AlCl3 + 3 H2 , the reaction of Al with HCl to produce hydrogen gas. What is the pressure of H2 if the

Margaret [11]

Answer : The pressure of hydrogen gas is 8.96 atm.

Explanation :

The given balanced chemical reaction is:

$2Al+6HCl\rightarrow 2AlCl_3+3H_2$

From the balanced chemical reaction we conclude that,

As, 2 moles of Al react to give 3 moles of $H_2$ gas

So, 4.50 moles of Al react to give $\frac{3}{2}\times 4.50=6.75$ moles of $H_2$ gas

Now we have to calculate the moles of $H_2$ gas when percent yield is 75.4.

$\text{The moles of }H_2=75.4\% \times 6.75=\frac{75.4}{100}\times 6.75=5.09moles$

Now we have to calculate the pressure of $H_2$ gas.

Using ideal gas equation :

PV = nRT

where,

P = Pressure of hydrogen gas = ?

V = Volume of the hydrogen gas = 14.0 L

n = number of moles of hydrogen gas = 5.09 moles

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of hydrogen gas = 300 K

Putting values in above equation, we get:

$P\times 14.0L=5.09mol\times 0.0821L.atm/mol.K\times 300K\\\\P=8.96atm$

Therefore, the pressure of hydrogen gas is 8.96 atm.

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3 years ago