First solve the area of the arrow, the arrow consist of a rectangle that has a dimensions of 10 ft x 18 ft. and the triangle has a base of 20 ft and the height is 6 ft.
A = xy + 0.5bh
where x and y are the dimensions of the rectangle
b is the base of the triangle
h is the height of the traingle
A = (10)(18) + 0.5(20)(6)
A = 240 sq ft
number can of paint = 240 sq ft ( 1 can / 100 sq ft)
=2.4 can of paint, since you cant purchase a fraction of the can then the he need to buy 3 cans of paint
Hope this helps!
P.S- Can you plz mark min as brainliest??
Thank You
Answer: When we rotate a figure of 90 degrees clockwise, each point of the given figure has to be changed from (x, y) to (y, -x) and graph the rotated figure.
Step-by-step explanation:
Hope this helps have a lovely day :)
Slope is also known as rise over run -
Here, we have the slope
. This means that the rise is
and the run is
. Since both values are positive, we can say that we go up one and we go right four. When we plot this on a graph (the graph is attached), we get the same exact formula we found. **In the graph, I plotted the line
**. Hope this helped!
Answer:
![f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } }](https://tex.z-dn.net/?f=%20f%27%28x%29%20%3D%20%20%20%5Cfrac%7B2%7Bx%7D%5E%7B2%7D%7D%7B%20%5Csqrt%5B3%5D%7B%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%20%7D%20%7D)
Step-by-step explanation:
![f(x) = ( {x}^{3} - 8)^{ \frac{2}{3} } \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2}{3} - 1 } (3 {x}^{2} - 0) \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2 - 3}{3} } \times 3 {x}^{2} \\ \\ f'(x) = 2{x}^{2}( {x}^{3} - 8)^{ \frac{ - 1}{3} } \\ \\ f'(x) = \frac{2{x}^{2}}{( {x}^{3} - 8)^{ \frac{ 1}{3} } } \\ \\ \huge \red{ \boxed{ f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } } }}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20f%27%28x%29%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20-%201%20%7D%20%283%20%7Bx%7D%5E%7B2%7D%20%20-%200%29%20%5C%5C%20%20%5C%5C%20f%27%28x%29%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B2%20-%203%7D%7B3%7D%20%20%7D%20%20%5Ctimes%203%20%7Bx%7D%5E%7B2%7D%20%5C%5C%20%20%5C%5C%20f%27%28x%29%20%3D%20%202%7Bx%7D%5E%7B2%7D%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B%20-%201%7D%7B3%7D%20%20%7D%20%5C%5C%20%20%5C%5C%20f%27%28x%29%20%3D%20%20%20%5Cfrac%7B2%7Bx%7D%5E%7B2%7D%7D%7B%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B%201%7D%7B3%7D%20%20%7D%20%7D%20%5C%5C%20%20%5C%5C%20%5Chuge%20%5Cred%7B%20%5Cboxed%7B%20f%27%28x%29%20%3D%20%20%20%5Cfrac%7B2%7Bx%7D%5E%7B2%7D%7D%7B%20%5Csqrt%5B3%5D%7B%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%20%7D%20%7D%20%7D%7D)
